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Amiraneli [1.4K]
3 years ago
12

You purchase a car in 2010 for $25,000. The value of the car decreases by 14% annually. What would the value of the car be in 20

20?
Mathematics
1 answer:
Fed [463]3 years ago
4 0

Answer: -$6,500

Step-by-step explanation:

Here we could , use the arithmetic progression where

T(2020 - 2010) = a + ( n - 1 )d

T10 = a + ( 10 - 1 )d --------------- 1

a = $25,000, n = 10 and d = 14% of $25,000 = $3,500 the common difference.

Note since it decreases the common difference d = -$3,500.

Now substitute for the values in the equation above.

T10 = 25,000 + 9 x -3,500

= $25,000 - $31,500

= -$6,500 (deficit )

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Put the following values in order from least<br> to greatest.<br> 20, 22, (-2)2 -22 -20
Elena L [17]

Answer:

-22, -20, (-2)2, 20, 22

Step-by-step explanation:

Negatives are smaller than positives but 22 is greater than 20 so we do -22, -20, (-2)2, (because -2*2 is -4), 20, 22

7 0
3 years ago
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Given the arithmetic sequence an = −5 + 3(n − 1), what is the domain for n?
Airida [17]
D because for a sequence you can't have a -1st term so b is out and a and c mean the same thing so neither of them can be the answer 
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What is the solution to the system of equations 2x+y=2 and y= -2x-2?
finlep [7]

Answer:

NO SOLUTION

Step-by-step explanation:

Solve this system by substitution:

Replace y in the first equation with -2x - 2:

2x + (-2x - 2) = 2, or

2x - 2x - 2 = 2

0 = 4      This is not possible, so this system has NO SOLUTION.

5 0
3 years ago
Could someone pkease help. i am not sure if i have the correct answer, thanks
Mama L [17]
I believe you are correct keep it up
5 0
3 years ago
Please help me find the area of shaded region and step by step​
Bumek [7]

Answer:

Part 1) A=60\ ft^2

Part 2) A=80\ cm^2

Part 3) A=96\ m^2

Part 4) A=144\ cm^2

Part 5) A=9\ m^2

Part 6) A=(49\pi -33)\ in^2

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

A=bh

where

b is the base of rectangle

h is the height of rectangle

so

A=(12)(7)-(8)(3)

A=84-24

A=60\ ft^2

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

A=b^2

where

b is the length side of the square

so

A=(12)(8)-(4^2)

A=96-16

A=80\ cm^2

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

A=4(4)(5)+(4^2)

A=80+16

A=96\ m^2

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

A=(15^2)-(9^2)

A=225-81

A=144\ cm^2

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

A=\frac{1}{2}(b)(h)

where

b is the base of triangle

h is the height of triangle

so

A=\frac{1}{2}(6)(7)-(6)(2)

A=21-12

A=9\ m^2

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

so

A=\pi (7^2)-(3)(11)

A=(49\pi -33)\ in^2

7 0
3 years ago
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