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3 years ago

4xy-3x+8y2-6y 8y-6 please help someone thank you

Mathematics

1 answer:

avanturin [10]3 years ago

6 0

Answer:

x=6, y=2.5

Step-by-step explanation:

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WILL GIVE BRAINLIEST<br> Solve for y in terms of w, x, and z.<br> x=zyw<br> y=

Advocard [28]

Answer:

y= x/zw

Step-by-step explanation:

Isolate the variable by dividing each side by the factors that dont contain the variable

x = zyw /zw

y=x/zw

3 0

3 years ago

Stephanie bought 36.5 inches of lumber at Home Depot the lumber cost 2.10 per inch including the sales tax. Stephanie bought 36.

tamaranim1 [39]

Answer:76.65

Step-by-step explanation:

First, you write 36.5 times 2.10

Then, multiply them.

That equals 76.65

4 0

3 years ago

Janet is painting her shed. She buys some gallon-sized paint cans that cost $15 each and 2 quart-sized paint cans that cost $4 e

blondinia [14]

1 gallon cost $15

1 quarts cost $4

1 quarts = 1/4 gallon

15x for number of gallon cans

2 cans at $4 each = $8

15x + 8 = 53

Subtract 8 from both sides:

15x = 53-8

15x = 45

Divide both sides by 15:

x = 45/15

x = 3

She bought 3 gallon cans of paint

Plus she bought 2 quart cans, which is equal to a half gallon.

She bought a total of 3.5 gallons of paint.

7 0

3 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

Amanda walked 2.5 miles to the post office and another 1.6 miles to the park then she walked home following the same route how f

adell [148]

2.5+2.5+1.6+1.6= 8.2 miles

Hope this helps!

8 0

3 years ago