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FinnZ [79.3K]
3 years ago
11

What is the length of s (the height of one of the triangular faces)?

Mathematics
1 answer:
Anestetic [448]3 years ago
5 0

Answer:

s = 16.2 units

Step-by-step explanation:

s^2 = 15^2 + 6^2   (6 is 1/2 of 12)

s^2 = 225 + 36

s^2 = 261

s = 16.16

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WILL GIVE BRAINLIEST HELP PLEASE
Tamiku [17]
The relation t relates x to y. To determine if it is a function, see if one x value can give two different y values. Since each x value only has one y value, the relation is a function. To check if the inverse is a function, see if any one y value will give multiple x values. By inversing t, there are two values of x for the value of y = -4 (x = 4 and x = 6), so this is NOT a function.

Answer: Relation t is a function. The inverse of relation t is NOT a function.
3 0
3 years ago
Please help me!<br> Find the number x such that f(x) =1
STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

f(x) = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

1 = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

This has two equations. So, we can separate them into two separate cases. Namely:

1=-\frac{1}{2}x-1\text{ or } 1=x

Let's solve for x in each case.

Case I:

We have:

1=-\frac{1}{2}x-1

Add 1 to both sides:

2=-\frac{1}{2}x

Let's cancel out the fraction by multiplying both sides by -2. So:

2(-2)=(-2)\frac{-1}{2}x

The right side cancels:

-4=x\\

Flip:

x=-4

So, x is -4.

Case II:

We have:

1=x

Flip:

x=1

This is the solution for our second case.

So, we have:

x_1=-4\text{ or } x_2=1

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

x_1=-4\text{ or } x_2=1

Out of our answer choices, we can pick D.

And we're done!

7 0
3 years ago
How is shape D diffrent from shapes A,B,C
Allushta [10]

Answer: D

Step-by-step explanation: Only has 2 acute angles and 2 obtuse angles

Let me know if I'm wrong. If not I'm glad I could help

5 0
2 years ago
Solve for x -3x+2=-11 please
larisa [96]

Answer:

6.5

Step-by-step explanation:

We need to solve out for x , the given Equation is ,

: \implies x - 3x + 2 = -11

: \implies -2x = -11 -2

: \implies -2x = -13

: \implies x = -13/-2

: \implies x = 6.5

4 0
3 years ago
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Does anyone know what the y-int is please help
tester [92]
I’m pretty sure it’s 1
5 0
2 years ago
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