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Zarrin [17]
3 years ago
13

Points Q and R are midpoints of the sides of triangle ABC.

Mathematics
2 answers:
givi [52]3 years ago
6 0

we know that

In the figure triangle ABC and triangle AQR are similar triangles

so

by proportion

\frac{QR}{AQ} =\frac{BC}{AB} \\ \\ \frac{2p+3}{4p} =\frac{6p-4}{8p} \\ \\ 2*(2p+3)=(6p-4)\\ \\ 4p+6=6p-4\\ \\ 6p-4p=6+4\\ \\ 2p=10\\ \\ p=5

AQ=4p\\ AQ=4*5\\ AQ=20\ units

therefore

<u>the answer is</u>

AQ is 20\ units

Alex787 [66]3 years ago
3 0
Set up that QR = BC/2

2p+3=3p-2

subtract 2p from each side and add two to each side

5=p

Plug in P to get your answer
Segment AQ=20 units
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15 computers for 45 students ; 45 computers for 135 students are they equivalent
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15 C for 45 S=15 C×3 for 45 S×3=45 C for 135 S
So, they are equivalent.
5 0
3 years ago
1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
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Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
A ball is such that when it is dropped from a height of 1 metre it bounces vertically from the ground
Phantasy [73]
Search mathpapa.com I get almost all my answers there
4 0
3 years ago
Half the difference of a number and 16 is negative 2
Reika [66]

Answer:

20

Step-by-step explanation:

Work backwards. If -2 x 2= -4 then something plus negative four will equal 16, which is 20.

7 0
3 years ago
If a girl has 4 seeds, 3 blue ones, and 1 purple one. What is the probability of her choosing a purple one?
Vanyuwa [196]

Answer:

¼

Step-by-step explanation:

From the question given above, the following data were obtained:

Blue (B) seed = 3

Purple (P) seed = 1

Total (S) = 1 + 3 = 4

The probability of her choosing a purple seed can be obtained as follow:

Event of purple seed, n(P) = 1

Total, n(S) = 4

Probability of purple seed, P(P) =?

P(P) = n(P) / n(S)

P(P) = ¼

Therefore, the probability of her choosing a purple seed is ¼.

4 0
3 years ago
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