I’m pretty sure it’s median because that’s what you would usually use for outliers.
The discriminante :
b^2-4ac
1^2 - 4 * -2 * -28 = 1 - 224 = -223
When the discriminant (b^2-4ac) is less than 0, the equation had no real solutions.
-223<0, so, 2x^2+x-28 = 0 has no real solutions.
Hope that helps :)
For this case we have that the original point is given by:
B = (7, 2)
As the point is reflected through the x axis, then we have the following transformation:
(x, y) --------------> (x, -y) -------------> (x ', y')
Applying the transformation to the original ordered pair we have:
(7, 2) --------------> (7, - (2)) -------------> (7, -2)
Answer:
Point B 'is given by:
B '= (7, -2)
To solve this I'm going to split the middle term.
First multiply the first and last terms:
24x^2
So find two numbers that multiply to 24x^2 and add to 11x.
This would be 3x and 8x
Rewrite the problem as
4x^2+3x+8x+6
Take the first and 3rd and 2nd and 4th terms
4x^2 and 8x
and
3x and 6
Factor by grouping
Take out a 4x for the first group to get 4x(x+2)
Take out a 3 for the 2nd group to get 3(x+2)
Rewrite as (4x+3)(x+2)
Hope this helps.
