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Katen [24]
3 years ago
13

The sum of two consecutive integers is greater than 50. Could 25 be one of the numbers?

Mathematics
2 answers:
GalinKa [24]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

25 + 26 = 51 greater than 50

AlekseyPX3 years ago
6 0

Answer:

Yes. 25 and 26 equal 51, so one of the consecutive numbers could be 25.

Step-by-step explanation:

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A charity organization had to sell 18 tickets to their fundraiser just to cover necessary production costs.
meriva

Answer: slope and x-intercept

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2 years ago
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You have 12 coins, one of which is fake. The fake coin is indistinguishable from the rest except that it is heavier. Can you det
Anton [14]
Yep! 
Weighing #1: Start off by splitting the pile of 12 coins evenly into two piles, 6 in each pile. Put one pile on each side of the balance. The side that is weighed down has the fake coin it in. Ignore the other 6 coins.

Weighing #2: Now you have 6 coins left. Split the pile evenly again, 3 in each pile. Repeat the same process and put each pile on one side of the balance. The side that is weighed down has your fake coin in it. Ignore the other 3 coins.

Weighing #3: You have 3 coins left. Take two coins, whichever two you like, and weigh them. If they weigh the same, then the one you didn't weigh is the fake one. If one is heavier, then that heavier one is your fake coin.
5 0
3 years ago
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A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
1 year ago
WILL GIVE BRAINLIEST!!!!!
Phoenix [80]
It’s either A or B but I would choose B as the correct answer
3 0
2 years ago
Please answer this with explanation. Please I really am struggling. I will mark you brainalist. Please solve it Please
Hatshy [7]

Answer:

13, 11, 4, 16, 6, 22

Step-by-step explanation:

<em>Let the second digit be x and the last digit be y</em>

Given:

  • Data set: 13, x, 4, 16, 6, y
  • Mean = 12
  • y = 2x or x = 2y

The mean of the data is the average. The average can be calculated by determining the sum of the terms and dividing it by the total digits.

\implies \text{Mean of data:} \ \dfrac{13 + x + 4 + 16 + 6 + y}{6} = 12

Let us substitute the value of y (2x) in the data.

\implies \dfrac{13 + x + 4 + 16 + 6 + 2x}{6} = 12

Now, add all the terms in the data and simplify.

\implies \dfrac{39 + x +2x}{6} = 12

\implies \dfrac{39 + 3x}{6} = 12

Distribute the denominators and simplify.

\implies \dfrac{39}{6} + \dfrac{3x}{6}  = 12

\implies  \dfrac{13}{2} + \dfrac{x}{2}  = 12

\implies  6.5 + \dfrac{x}{2}  = 12

Subtract 6.5 both sides and simplify.

\implies  6.5 + \dfrac{x}{2}  - 6.5 = 12 - 6.5

\implies \dfrac{x}{2} = 5.5

Use cross multiplication and simplify.

\implies x= 5.5 \times 2

\implies  x= 11

To determine the value of "y", simply substitute the value of "x" into the expression that represents the value of "y".

\implies y = 2x

\implies y = 2(11)

\implies y = 22

When the x and y values are substituted in the data, we get;

  • ⇒ 13, 11, 4, 16, 6, 22

Therefore, the data is 13, 11, 4, 16, 6, 22.

8 0
2 years ago
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