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olya-2409 [2.1K]
3 years ago
10

2/4, find the surface area

Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

144 un^2

Step-by-step explanation:

Base: 4 × 11 = 44

Left-most face: 3 × 11 = 33

Top face: 5 × 11 = 55

Triangular faces: 3 × 4 = 12

Add: 44 + 33 + 55 + 12 = 144

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Carmine buys 2 plates for $4 each. He also buys 12 bowls. Each bowl costs twice as much as each plate. The store is having a sal
Tasya [4]

Answer

2p+12b=12

Step-by step explanation

I used p for plates and b for bowls\

2p+12b=4+(4*2)

2p+12b=12

4 0
3 years ago
Read 2 more answers
Question 1 (1 point)
olya-2409 [2.1K]

For this case we can propose a system of equations:

x: Let the variable that represents the number of small cookies

y: Let the variable that represents the number of large cookies

According to the statement we have:

x + y = 130\\2x + 3y = 310

We multiply the first equation by -2:

-2x-2y = -260

We have the following equivalent system:

-2x-2y = -260\\2x + 3y = 310

We add the equations:

-2x + 2x-2y + 3y = -260 + 310\\y = 50

We look for the value of the variable "x":

x = 130-y\\x = 130-50\\x = 80

Answer:

They sold 80 small cookies and 50 large cookies

6 0
3 years ago
Nvmmm jdkslkdijewkl,jdkr3tfrrrrrrrrredsw
kaheart [24]

hmmm, between the three options I would go with the second one since the number of 1-foot cubes equals exactly the volume of the fish tank.

But to truly calculate the volume

5 x 3 = 15

15 x 3 = 45

45 is the volume of the fish tank

3 0
2 years ago
Write a word sentence for the equation 2.3m = 0.46
Levart [38]
Two point three mequals zero point fourty six
6 0
4 years ago
Read 2 more answers
Delaney would like to make a 10 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of peanuts and severa
scoundrel [369]

Answer:

a) p + m = 10 and \frac{p + 0.2m}{0.8m} = \frac{60}{40}

b) The mixing amount is 5 lb peanut and 5 lb mixture.

Step-by-step explanation:

Given that p pounds of peanuts and m pounds of the 80% almond and 20% peanut mixture are used to make 10 pounds of 60% peanuts and 40% of almonds mixture.

Now, we can write that p + m = 10 ........ (1)  

Now, m pounds of 80% almond and 20% peanut mixture contain 0.2m pounds of peanuts and 0.8m pounds of almonds.

Now, from the condition given it can be written that  

\frac{p + 0.2m}{0.8m} = \frac{60}{40} .......... (2)

⇒ \frac{p + 0.2m}{0.8m} = \frac{3}{2}

⇒ 2p + 0.4m = 2.4m

⇒ 2p = 2m

⇒ p = m  

Now from equation (1) we get p = m = 5 pounds.

a) Therefore, equations (1) and (2) are the system of equations that models the situation.

b) The mixing amount is 5 lb peanut and 5 lb mixture. (Answer)

3 0
3 years ago
Read 2 more answers
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