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Anon25 [30]
3 years ago
8

Carmine buys 2 plates for $4 each. He also buys 12 bowls. Each bowl costs twice as much as each plate. The store is having a sal

e that gives Carmine $4 off the total cost of the bowls.
Which numerical expression shows how much he spent?
Mathematics
2 answers:
Travka [436]3 years ago
7 0

Answer: 156

Step-by-step explanation:

4 x4 is 16

16-4=12

12¹² = 156

Maybe (-_-;)・・・

Tasya [4]3 years ago
4 0

Answer

2p+12b=12

Step-by step explanation

I used p for plates and b for bowls\

2p+12b=4+(4*2)

2p+12b=12

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Marilyn a 320 pounds of vegetables last week how many ounces did she eat per month and rounded to the nearest tenth?
max2010maxim [7]
1 lb = 16 oz

320 lbs = 5,120 oz

5,120 * 4 = 20,480 oz

She ate 20,480 oz of vegetables per month. That was my answer as a whole number.
4 0
3 years ago
If i can get an answer by tom i would really apreciate it.<br><br>=D
Yanka [14]
Only one section should be coloured in because it's 1/8 of the spinner. Meaning, there is one chance of landing on any colour.
3 0
3 years ago
Please help me please!<br> Also, please show your work image shown below in attachment
WINSTONCH [101]

Answer:

see below

Step-by-step explanation:

some of your answers that you currently have are wrong, I'll note those mistakes below

- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio

5x+15 = 5(x+3), not (x+3)(x+5)

ie  \frac{10x^2+20x}{x+2}

we see that 10x can divide the numerator in a whole number ratio

10x^2+20x = 10x(x+2), not (x+2)(x+10)

second mistake: the first binomial expansion is incorrect.

you have the expansion formula right, but you added terms wrong, go look at it again

3. x^2+3x+2/ x^2+5x+6

(x+1)(x+2)/(x+3)(x+2)

(x+1)/(x+3)

4. (x^2+6x+8)/(x^2-16)

(x+4)(x+2)/(x+4)(x-4)

(x+2)/(x-4)

5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator

6. (x^4y^6)^2

(x^4y^6)(x^4y^6) = x^8y^{12}

remember that (x^a)(x^b) = x^(a+b)

or remember that (x^a)^b = x^ab

6 0
3 years ago
PLEASE HELP !!!!!!!!!!!!!
Akimi4 [234]

9514 1404 393

Answer:

  the multiplicity is 4

Step-by-step explanation:

The graph shows a root at x = -2 that has a multiplicity of 2. You know the multiplicity is even, because the graph does not cross the x-axis. The multiplicity is 2 because the general shape of the graph in that area matches that of a quadratic (parabola).

The multiplicity of the root at x=4 is also an even number, because the x-axis is not crossed. However, the graph is significantly flatter at that point (than at x=-2), meaning the multiplicity is greater than 2. It is at least 4.

When we draw a graph with a multiplicity of 6 at x=4, we find the ratio of the peaks near x=-4 and x=0 to be different from that shown here. The suggests that the multiplicity of the root at x=4 is exactly 4.

4 0
3 years ago
A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa
Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = \frac{12!}{3! 3! 3! 3!}

Now,

The Total number of ways in which Remaining cards are distributed = \frac{40!}{10! 10! 10! 10!}

So,

Total number of ways of getting 3 picture card and remaining card = \frac{12!}{3! 3! 3! 3!}× \frac{40!}{10! 10! 10! 10!}

= \frac{12! 40!}{(3!)^{4} (10!)^{4}  }

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = \frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }

∴ The probability = \frac{\frac{12! 40!}{(3!)^{4} (10!)^{4}  }}{\frac{52!}{(13!)^{4} }}

                            = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13!)^{4} }{ 52! }

                           = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }

                           = \frac{12!}{(3!)^{4}   }×\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = \frac{479,001,600}{(6)^{4}   }×\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0
3 years ago
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