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3 years ago

What does it mean for a variable to have coefficients that are equal but opposite

1 answer:

5 0

A coefficient goes before a variable and is a constant. When the coefficients are equal but opposite it means you have an even function.

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HELP HELP HELP Quick algebra 1 questions

beks73 [17]

Hello:

Okay, this problem should be taken in a series of steps:

What is the slope's formula?

$\rm\hookrightarrow \frac{y_2-y_1}{x_2-x_1}$

(x₁,y₁) -- first point
(x₂,y₂) -- second point

Okay, now let's use this knowledge

10. (5,-19) and (-5,21)

$Slope = \frac{21--19}{-5-5} =\frac{40}{-10}=-4$

11. (12,1) and (12, -1)

$Slope = \frac{-1-1}{12-12} =\frac{-2}{0}$

12. (8,7) and (4,7)

$Slope = \frac{7-7}{4-7} =0$

Answer:

Question 10: -4
Question 11: undefined
Question 12: 0

Hopefully that helps!

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2 years ago

Drop your insta i dont know what to put they asked for 20 or more so this should work

zlopas [31]

Answer:

underated.jay

Step-by-step explanation:

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3 years ago

PLEASE Help ....... Will mark brainliest

Andru [333]

The formula for determining the pressure, p, exerted on an object at a depth, h, below the surface of a liquid is p = s + dgh, where s is the atmospheric pressure, d is the density of the liquid, and gas the acceleration due to gravity.

p = s + dgh

dgh = p - s

h = (p - s)/dg

Which formula represents h in terms of p, s, d, and g? Formula B is correct.

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3 years ago

I WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Suppose that

Diano4ka-milaya [45]

Answer:

sin(B) = 12/13

cos(B) = 5/13

tan(B) = 12/5

csc(B) = 13/12

sec(B) = 13/5

cot(B) = 5/12

Step-by-step explanation:

If ABC is a right triangle, assuming that ∠C = 90°, then the segment AB =13 is the hypotenuse and the other two sides are:

$BC = 5\\AC = \sqrt{13^2 - 5^2}\\AC = 12$

The six trigonometric functions of angle B are:

$sin(B) =\frac{AC}{AB}= \frac{12}{13}\\cos(B) = \frac{BC}{AB} =\frac{5}{13}\\tan(B) = \frac{AC}{BC} =\frac{12}{5}\\\csc(B) =\frac{1}{sin(B)}= \frac{13}{12}\\sec(B) = \frac{1}{cos(B)} =\frac{13}{5}\\cot(B) = \frac{1}{tan(B)} =\frac{5}{12}\\$

7 0

3 years ago