The answer is 4.7 x 10^-4
If you move the decimal to the right, the exponent will be negative. If you move it to the left, the exponent will be positive.
Answer:
The number of words that can be formed from the word "LITERATURE" is 453600
Step-by-step explanation:
Given
Word: LITERATURE
Required: Number of 10 letter word that can be formed
The number of letters in the word "LITERATURE" is 10
But some letters are repeated; These letters are T, E and R.
Each of the letters are repeated twice (2 times)
i.e.
Number of T = 2
Number of E = 2
Number of R = 2
To calculate the number of words that can be formed, the total number of possible arrangements will be divided by arrangement of each repeated character. This is done as follows;
Number of words that can be formed = 
Number of words = 
Number of words = 
Number of words = 453600
Hence, the number of words that can be formed from the word "LITERATURE" is 453600
Half the x-coefficient is -3, so the equation needs to be rearranged into a form that looks like
x² -6x +(-3)² + [something]
You can get there by adding and subtracting 9 from the original equation.
y = x² -6x +9 +7 -9 . . . . . 9 added and subtracted
y = (x² -6x +9) -2
The quantity in parentheses is a perfect square, so we can write the equation in the desired form as ...
y = (x -3)² -2
To find the answer we start by adding the contents of both containers together
7.49 + 6.26 = 13.75
Since we know that there is leftover paint we are going to subtract the leftovers from the total of combined paint
13.75 - 0.43 = 13.32
The combined paint is poured into 4 containers so we divide our combined total minus the leftovers by 4
13.32/4 = 3.33
Answer: There are 3.33 liters of paint in each container
i. The Lagrangian is

with critical points whenever



- If
, then
. - If
, then
. - Either value of
found above requires that either
or
, so we get the same critical points as in the previous two cases.
We have
,
,
, and
, so
has a minimum value of 9 and a maximum value of 182.25.
ii. The Lagrangian is

with critical points whenever
(because we assume
)



- If
, then
. - If
, then
, and with
we have
.
We have
,
,
, and
. So
has a maximum value of 61 and a minimum value of -60.