The answer to this question is 7/14.
Using the y = mx + b formula
C = 225s + 3500
Then to transport 19 tons
C = 225(19) + 3500
C = 4275 + 3500
C = 7775
If you project S onto the (x,y)-plane, it casts a "shadow" corresponding to the trapezoidal region
T = {(x,y) : 0 ≤ x ≤ 10 - y and -4 ≤ y ≤ 4}
Let z = f(x, y) = √(16 - y²) and z = g(x, y) = -√(16 - y²), each referring to one half of the cylinder to either side of the plane z = 0.
The surface element for the "positive" half is
dS = √(1 + (∂f/∂x)² + (∂f/dy)²) dx dy
dS = √(1 + 0 + 4y²/(16 - y²)) dx dy
dS = √((16 + 3y²)/(16 - y²)) dx dy
The the surface integral along this half is




You'll find that the integral over the "negative" half has the same value, but multiplied by -1. Then the overall surface integral is 0.
Answer:
x-intercept (s):
For this case h (x) = 0
x2 - 2x - 8 = 0
(x-4) * (x + 2) = 0
x1 = 4
x2 = -2
y-intercept:
For this case x = 0
h (0) = (0)2 - 2 (0) - 8
h (0) = - 8
vertex:
We derive the equation:
h '(x) = x2 - 2x - 8
h (x) = 2x - 2
We match zero:
2x-2 = 0
x = 2/2
x = 1
We evaluate the function for x = 1
h (1) = (1)2 - 2 (1) - 8
h (1) = 1 - 2 - 8
h (1) = -9
The vertex is:
(1, -9)
axis of symmetry of the function:
x = 1
Step-by-step explanation:
hope it helps
Answer:


Step-by-step explanation:
<u>Sample Space</u>
The sample space of a random experience is a set of all the possible outcomes of that experience. It's usually denoted by the letter
.
We have a number cube with all faces labeled from 1 to 6. That cube is to be rolled once. The visible number shown in the cube is recorded as the outcome. The possible outcomes are listed as the sample space below:

Now we are required to give the outcomes for the event of rolling a number less than 5. Let's call A to such event. The set of possible outcomes for A has all the numbers from 1 to 4 as follows
