All categories

3 years ago

Find the Area of the circle

Mathematics

1 answer:

Vlad1618 [11]3 years ago

5 0

Answer: 530 cm^2

Step-by-step explanation:

A = 3.14 * r^2

A = 3.14 * 13 * 13

A = 3.14 * 169

A = 530 cm ^2

You might be interested in

Nate spent $28 on 2 dvds.at this rate how much would 5 dvds cost him

Anuta_ua [19.1K]

2=28 divide both get 14 . So each cd is 14$. So now 28+28=56 (4 cd's) plus 14 (1 more cd) =5 so 5 is 70.

7 0

3 years ago

Find the surface area

Nikitich [7]

The answer to the question is that the surface area is 48

3 0

3 years ago

(-3c+6) + (-c+8) simplify with a step by step please

mel-nik [20]

Step-by-step explanation:

$= ( - 3c + 6) + ( - c + 8)$

$= - 3c + 6 - c + 8$

$= - 3c - c + 6 + 8$

= -4c + 14

hence -4c + 14 is the answer ...

hope it helped !!

6 0

2 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

3 years ago

I’m confused on this one

kvv77 [185]

The answer is 42.

The question is asking for angle N. We know from the question that angle N is equal to angle E (Don't think about the scale factor because it only applies to the sides. They're just trying to trick you).

To find angle E:
$79 + 6x + 11 + 7x - 14 = 180$
Move numbers to the right side:
$6x + 7x = 180 - 79 - 11 + 14$
Combine like terms:
$13x = 104$
Divide both sides by 13:
$x = 8$
The formula for angle E:
$7x - 14$
Plug in the 8:
$7 \times 8 - 14 = 56 - 14 = 42$
The angle measure of E is 42. So angle N is automatically 42 too.

To solidify, we can try to use the formula which they give us for angle N:
$3x + 18 = 24 + 18 = 42$

8 0

3 years ago