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mr Goodwill [35]
4 years ago
9

Solve the following equation T/4 +7 =2.

Mathematics
2 answers:
Sindrei [870]4 years ago
4 0

Answer:

T=-20

Step-by-step explanation:

first get rid of the 7

1. T/4=-5

then multiply by 4 to isolate T

2. T=-20

Annette [7]4 years ago
4 0

Answer:

T = -20

Step-by-step explanation:

T/4 +7 =2.

Subtract 7 from each side

T/4 +7-7 =2-7

T/4 = -5

Multiply each side by 4

T/4 *4 = -5*4

T = -20

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2x - 3 = sally's berries

x= jim's berries

2x - 3 + x = 21 } equation
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8 0
4 years ago
Rt-2n=y solve for t<br> show step-by-step solution
vfiekz [6]
The answer is t = (y + 2n)/r

The expression is: rt - 2n = y
Rearrange it so that only rt is on the left side of the equation: rt = y + 2n
Rewrite the left side of the equation: r * t = y + 2n
Divide both sides of the equation by r: r * t / r = (y + 2n)/r
r can be cancelled out on the left side of the equation: t = (y + 2n)/r

8 0
3 years ago
If Tim had lunch at $50.50 and he gave 20% tip, how much did he spend?
Diano4ka-milaya [45]

Answer:

<h2> Tim spent $60.60 for his lunch.</h2>

Step-by-step explanation:

The tip is 20% of what he paid for lunch. Hence

tip = 20% of 50.50 = (20/100)*50.50 = 101/100 = $10.10

Total spent

50.50 + 10.10 = $60.60

So hence, Tim spent $60.60 for his lunch.

-----------------------------------------------------------—-----------------------------------------------

Thanks!

Mark me brainliest!

~FieryAnswererGT~

3 0
2 years ago
Read 2 more answers
Given the two triangles are similar, what is the value of s? (DO NOT round your answer.)
Trava [24]

Answer:

the value of s is 7.5 ...............

7 0
3 years ago
Read 2 more answers
Help!!!!!!!!!!!!!!!!
Andru [333]

Step-by-step explanation:

The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:

let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9

let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9

let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9

let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9

let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9

let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9

You can continue to increase the length of the square and follow this pattern and it will be consistent.

7 0
3 years ago
Read 2 more answers
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