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Dennis_Churaev [7]
3 years ago
7

Please help me!! I really need it!! I Could fail the 7th grade

Mathematics
1 answer:
babymother [125]3 years ago
7 0

Answer:

Step-by-step explanation:

Price of one ticket   = $4

Price of t tickets = 4t

1) 4t + 72 > 400

   t >  (400-72)/4

2) 4t + 72 > 400      

4t + 72 - 72 > 400 - 72    {subtract 72 from both sides}

4t > 328

4t/4 > 328/4      {divide both sides  by 4}

t >  82

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If you're using the app, try seeing this answer through your browser:  brainly.com/question/3166243

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Solve the trigonometric equation:

     \mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}


Make a substitution:

     \mathsf{cos\,x=t\qquad (-1\le t\le 1)}

and the equation becomes

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Rewrite conveniently  – t  as  + t – 2t,  and then factor the left-hand side by grouping:

      \mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}


Factor out  2t + 1:

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Substitute back for  t = cos x:

     \begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}


Therefore,

     \begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}

where  k  is an integer.


Solution set:   

\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}


I hope this helps. =)

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Answer:

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