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ohaa [14]
3 years ago
8

What is (5,-4) y=-3/5+4

Mathematics
1 answer:
Sergio039 [100]3 years ago
5 0

Answer:

Simplify both sides of the equation.

y= 17/5

Apologies if I am incorrect.

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Question One
Volgvan

Answer:

7:11

Step-by-step explanation:

No of linemen = 7

No of running backs = 2

No of fullback = 1

No of quarterback =1

The total no of players on the team = 7+2+1+1 = 11

We need to find the ratio of the number of linemen to the total number of players on the team.

R = 7/11

or

R = 7:11

Hence, the required ratio is 7:11.

8 0
3 years ago
Please do them step by step;
ELEN [110]
For the first one c-9=(2)(4)+6
You are gonna multiply 2 and 4 first, 2*4=8. Now you have c-9=8+6. 8+6=14. So now the equation is c-9=14. Now we are going to add 9 to both sides. So c=23
For the second equation 10+y=90. We are going to subtract 10 from both sides. So, y=80.
Third, add 4 to both sides. a=10.
Fourth, subtract 8 from both sides. d=-9
Fifth, 5+2(3+4)=-x.
First we are going to add 3 and 4. 3+4=7. 5+2(7)=-x. Next we are going to multiply 2 and 7. 2*7=14. 5+14=-x. 5+14=19. So our equation is 19=-x. Next we are going to multiply both sides by -1. Making our final equation x=-19.
c=23
y=80
a=10
d=-9
x=-19
I hope that helps, if you need any further explanation just ask.<span />
3 0
3 years ago
The Pythagorean Theorem and Irrational numbers
Natalka [10]
49=16+x^2
x^2= 33
x= square root of 33
3 0
3 years ago
The Venn diagram shows the results of two events resulting from rolling a number cube.
tankabanditka [31]

Answer:

P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{1}{3}

P(A) =\frac{2}{3}

P(B) =\frac{1}{2}.

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

So

P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

So

P(A) = \frac{4}{6} = \frac{2}{3}

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

So

P(B) = \frac{3}{6} = \frac{1}{2}.

Now

P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}

6 0
3 years ago
Solve the system below by elimination -2x-9y=-25
xz_007 [3.2K]
I think it’s 2x+9y-25=0
3 0
3 years ago
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