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Svetlanka [38]
3 years ago
8

HELP PLEASE I have no clue what this is

Mathematics
2 answers:
devlian [24]3 years ago
7 0

Answer:

972

Step-by-step explanation:

Kamila [148]3 years ago
4 0

Answer:

B

Step-by-step explanation:

The volume (V) of a sphere is calculated using the formula

V = \frac{4}{3} πr³ ← r is the radius

here r = 9, so

V = \frac{4}{3} × π × 9³

   = \frac{4}{3} × π × 729

   = \frac{4(729)\pi }{3} = \frac{2916\pi }{3} = 972 π m³

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3 years ago
13 subtracted from a number x
Nesterboy [21]
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I need help plzz
sesenic [268]

Answer:

3200

Step-by-step explanation:

8 0
3 years ago
Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f
GalinKa [24]

Answer:

\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in \mathbb{R}.

\\f(x)=(x^2+16)(x^2-2x-15)

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}

And we can write in \mathbb{C}

f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0
3 years ago
Help me, I’ll give you brainliest. :)
lions [1.4K]

Answer:

72, give me brainliest please

6 0
2 years ago
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