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mars1129 [50]
3 years ago
15

In triangle NOP p equals 600 inches angle P equals 96° and angle N equals 64° what is the area of triangle NOP to the nearest 10

th of a square inch?
Mathematics
1 answer:
DochEvi [55]3 years ago
7 0

9514 1404 393

Answer:

  55,637.8 square inches

Step-by-step explanation:

We can find side n using the Law of Sines:

  n/sin(N) = p/sin(P)

  n = p(sin(N)/sin(P)) = 600·sin(64°)/sin(96°)

  n ≈ 542.246913 . . . . inches

The angle O is ...

  O = 180° -N -P = 180° -64° -96° = 20°

Then the area is ...

  A = 1/2·np·sin(O)

  A = (1/2)(542.246913 in)(600 in)·sin(20°) ≈ 55,637.81008 in²

The area of ∆NOP is about 55,637.8 in².

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What is the equation of the line that passes through (5, 3) and (4, 5)
lara31 [8.8K]

Answer:

y = - 2x + 13

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (5, 3) and (x₂, y₂ ) = (4, 5)

m = \frac{5-3}{4-5} = \frac{2}{-1} = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (4, 5), then

5 = - 8 + c ⇒ c = 5 + 8 = 13

y = - 2x + 13 ← equation of line

7 0
3 years ago
A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears
arsen [322]

Answer:

The correct answer is "0.0000039110".

Step-by-step explanation:

The given values are:

Y_n\rightarrow N(\mu, \sigma^2)

\mu = 40n

\sigma^2=100n

n=20

then,

The required probability will be:

= P(Y_{20}>1000)

= P(\frac{Y_{20}-\mu}{\sigma} >\frac{1000-40\times 20}{\sqrt{100\times 20} } )

= P(Z>\frac{1000-800}{44.7214} )

= P(Z>\frac{200}{44.7214} )

= P(Z>4.47)

By using the table, we get

= 0.0000039110

6 0
3 years ago
When solving the equation 10x + 2 = 22, what is the first thing you're going to do?
Tasya [4]
I would minus 2 from both sides of the equation so that it becomes:

10x \:  =  \: 20
4 0
3 years ago
Read 2 more answers
how do you have a reflection in the x axis, if the shape is already partially in the third and second quadrent of the graph
IgorLugansk [536]

Its a reflection over an x-axis, whats "positive" goes "negative" and whats "negative" goes "positive" with respect to y.

If a shape S is a subset (made of P_2\cup P_3 of quadrants Q_2,Q_3 then the part P_2 that lies in the second quadrant gets mapped to Q_3 and part P_3 that lies in third quadrant gets mapped to Q_2

Hope this helps.

8 0
2 years ago
Whats 318,224,475 rounded too the nearest ten.​
aivan3 [116]
318,224,480

5 is in the ones place so u round up
8 0
3 years ago
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