y - 3
g(y) = ------------------
y^2 - 3y + 9
To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
(y^2 - 3y + 9)^2
Note carefully: The denom. has no real roots, so division by zero is not going to be an issue here.
Simplifying the denominator of the derivative,
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3) => y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
-y^2 + 6y
Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6. These are your critical values. You may or may not have max or min at one or the other.
g(1)=-1 : We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.
So, g(1)=-1 is false.
g(0)=0 : We need to check values of function for x=0. From the graph, we can see, for x=0 the value of y is 0.
So, g(0) =0 is true.
g(4)=-2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to -2.
So, g(4)=-2 is false.
g(1)=1 :We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.
So, g(1) =1 is true.
g(-1)=1 :We need to check values of function for x=-1. From the graph, we can see, for x=-1 the value of y is 1.
So, g(-1)=1 is true.
g(4)=2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to 2.
So, g(4)=2 is false.
Answer:
5540.340 is rounded to the 3rd decimal place
4,3,2,5, 6, 6, 10, 5, 6, 2, 3, 4, 6, 7, 14,5<br>
1. What is the mean of the data set?
tankabanditka [31]
Answer:5.5
Step-by-step explanation:
when all the numbers are added up =88
88 divide by 16 because their is 16 numbers in this sequence=5.5