A. X Z Y
B. P N M
C. F E H G D
Answer:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the z-score that has a p-value of
.
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.
This means that 
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Answer:
ABOUT 13 PERCENT
Step-by-step explanation:
I AM NOT CERTAIN BUT I GOT IT BY:
NEW PRICE - OLD PRICE divided by OLD PRICE X 100
<h3>
Therefore either
or, 
</h3>
Step-by-step explanation:

here a = 3 ,b = 9 and c= -6



Therefore either
or, 
∠1 = ∠2
2x +10 = 3x -6
16 = x . . . . . . . . . . . add 6-2x
Selection B is appropriate.