A cylindrical bucket contains 615 cubic inches of water the heigh of the water is 4 inches what is the radius of the bucket to t
1 answer:
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Answer:
<em>AB = 7.35 cm</em>
Step-by-step explanation:
From the attachment,
In ΔDEF,
DF = GH-(GD+FH) = 6 - (2+3) = 1 cm
DE = 2+3 = 5 cm (sum of two radius)
Applying Pythagoras theorem,
In ΔCDI,
DI = GH-(GD+IH) = 6 - (2+1.5) = 2.5 cm
CD = 2+1.5 = 3.5 cm (sum of two radius)
Applying Pythagoras theorem,
AB = EF + CI =
