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Yuri [45]
3 years ago
10

Solve the system of equations by substitution. What is the solution for x?

Mathematics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

x=0.875

Step-by-step explanation:

2×+y=1

y=0.5

4×+2y=-1

4×+2.5=-1

1+2.5=4x

3.5=4x

x=0.875

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I’ll give u the crown
expeople1 [14]

Answer:

She will go to 729 games in 162 days.

Step-by-step explanation:

27÷6 = 4.5

4.5 · 162 = 729

4 0
2 years ago
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A radio disc jockey has 7 songs on this up coming hour's playlist: 2 are rock songs, 2 are reggae songs and 3 are country songs.
SVETLANKA909090 [29]

Answer:

Probability that song selected after first selection is rock = 2/7

Probability that song selected from the remaining after second selection is country rock = 1/2

Step-by-step explanation:

Total number of songs = 7

After first selection, probability that the song selected is rock = 2/7

After second selection, probability that the song selected from the remaining is a country song = 3/6 = 1/2

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3 years ago
Solve for x 5x+7=9x-25
Svetlanka [38]
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Subtract 9x both side
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6 0
3 years ago
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10. if ABC is equilaterteral, solve for x​
djyliett [7]

Answer:

13

Step-by-step explanation:

If ABC is equilaterteral then all the angles must be equal and 60°

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x = 13

8 0
3 years ago
Help with 5b please . thank you.​
Allushta [10]

Answer:

See explanation

Step-by-step explanation:

We are given f(x)=ln(1+x)-x+(1/2)x^2.

We are first ask to differentiate this.

We will need chain rule for first term and power rule for all three terms.

f'(x)=(1+x)'/(1+x)-(1)+(1/2)×2x

f'(x)=(0+1)/(1+x)-(1)+x

f'(x)=1/(1+x)-(1)+x

We are then ask to prove if x is positive then f is positive.

I'm thinking they want us to use the derivative part in our answer.

Let's look at the critical numbers.

f' is undefined at x=-1 and it also makes f undefined.

Let's see if we can find when expression is 0.

1/(1+x)-(1)+x=0

Find common denominator:

1/(1+x)-(1+x)/(1+x)+x(1+x)/(1+x)=0

(1-1-x+x+x^2)/(1+x)=0

A fraction can only be zero when it's numerator is.

Simplify numerator equal 0:

x^2=0

This happens at x=0.

This means the expression,f, is increasing or decreasing after x=0. Let's found out what's happening there. f'(1)=1/(1+1)-(1)+1=1/2 which means after x=0, f is increasing since f'>0 after x=0.

So we should see increasing values of f when we up the value for x after 0.

Plugging in 0 gives: f(0)=ln(1+0)-0+(1/2)0^2=0.

So any value f, after this x=0, should be higher than 0 since f(0)=0 and f' told us f in increasing after x equals 0.

8 0
2 years ago
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