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FromTheMoon [43]
3 years ago
10

What are the solutions to the equation

Formula1" title=" |x - 8| + 2 = 20" alt=" |x - 8| + 2 = 20" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
nexus9112 [7]3 years ago
8 0

Answer:

Solutions are -10 and 26

Step-by-step explanation:

( - the abolute sign I'm using

( x - 8 ) + 2 = 20

( x - 8 ) = 18

x - 8 = 18 (postive case)

x - 8 + 8 = 18 + 8

x = 26

( x - 8 ) = 18

x - 8 = -18 (negative case)

x - 8 + 8 = -18 + 8

x = -10

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3 years ago
Factor this expression completely, then place the factors in the proper location on the grid. a^3y + 1
ivolga24 [154]

Answer:

a^{3y} + 1  = (a^{y}+1 )^{3}  - 3a^y(a^{y}+1)\\\\

Step-by-step explanation:

We are to factorize the expression a^{3y} + 1 completely. To do this, we will apply the expression below;

The expression can be rewritten as a^{3y} + 1^{3}

To factorize the expression, we need to first factorize (a^{y}+1 )^{3} first

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The we will make a^{3y} + 1^{3} the subject of the formula as shown;

(a^y)^{3} + 1 = (a^{y}+1 )^{3}  - (3(a^y)^{2}+3a^y)\\(a^y)^{3} + 1^{3}  = (a^{y}+1 )^{3}  - (3(a^y)^{2}+3a^y)\\\\

(a^y)^{3} + 1  = (a^{y}+1 )^{3}  - (3(a^y)^{2}+3a^y)\\\\

a^{3y} + 1  = (a^{y}+1 )^{3}  - (3(a^y)^{2}+3a^y)\\\\

a^{3y} + 1  = (a^{y}+1 )^{3}  - 3a^y(a^{y}+1)\\\\

This last result gives the expansion of the expression

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Step-by-step explanation:

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