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3 years ago

Which one of the following equations correctly represents the process relating to the ionization energy of X?

Physics

1 answer:

Naily [24]3 years ago

7 0

Answer:

The correct option is E. X(g) → X⁺(g) + e⁻

Explanation:

The electrons are attracted to the nucleus and it is necessary to provide energy to start them. Then the ionization energy is the energy necessary to pull an electron to a gaseous atom, isolated and in a fundamental state. The electrons in the last shell are the most weakly attracted to the nucleus, so these are the lost electrons.

In this way, the gaseous element is converted to a gaseous cation (positively charged ion).

Taking this definition into account, <u><em>the correct option is E. X(g) → X⁺(g) + e⁻</em></u>

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Pam has a mass of 42.4 kg and she is at rest on smooth, level, frictionless ice. Pam straps on a rocket pack. The rocket supplie

fredd [130]

Answer:

F = 2349.6 N

Explanation:

We can solve this exercise using the relationship of momentum and momentum

I = Δp

I = F t

As the woman accelerates at a distance of 29.1 m to go from rest to 56.8 m / s, we can use the kinematics to find the acceleration

v² = v₀² + 2 a x

v₀ = 0

a = v / 2x

a = 56.8 2/2 29.1

a = 55.43 m / s²

Let's look for the time you need to get this speed

v = v₀ + a t

t = v / a

t = 56.8 / 55.43

t = 1,025 s

Let's clear the average force momentum from the momentum

F t = m v- m v₀

F = mv / t

F = 42.4 56.8 / 1.025

F = 2349.6 N

3 0

3 years ago

In 2017, the company SpaceX became the first private company to send supplies to the International Space Station with a reusable

pav-90 [236]

Answer:

Approximately $3.98\; \rm m \cdot s^{-2}$ .

Assumption: air resistance on the rocket is negligible. Take $g = \rm 9.81\; m \cdot s^{-2}$ .

Explanation:

By Newton's Second Law of Motion, the acceleration of the rocket is proportional to the net force on it.

$\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ .

Note that in this case, the uppercase letter $\rm M$ in the units stands for "mega-", which is the same as $10^6$ times the unit that follows. For example, $\rm 1\; Mg = 10^6\; g$ , while $\rm 1\; MN = 10^6\; N$ .

Convert the mass of the rocket and the thrust of its engines to SI standard units:

The standard unit for mass is kilograms: $\displaystyle m = \rm 552\; Mg = 552 \times 10^6\; g \times \frac{1\; \rm kg}{10^3\; g} = 552 \times 10^3 \; kg$ .
The standard for forces (including thrust) is Newtons: $\text{Thrust} = \rm 7.61 \; MN = 7.61 \times 10^6\; N$ .

At launch, the velocity of the rocket would be pretty low. Hence, compared to thrust and weight, the air resistance on the rocket would be pretty negligible. The two main forces that contribute to the net force of the rocket would be:

Thrust (which is supposed to go upwards), and
Weight (downwards due to gravity.)

The thrust on the rocket is already known to be $\rm 7.61 \times 10^6\; N$ . Since the rocket is quite close to the ground, the gravitational acceleration on it should be approximately $9.81\; \rm m \cdot s^{-2} = 9.81 \; N \cdot kg^{-1}$ . Hence, the weight on the rocket would be approximately $9.81\; \rm N \cdot kg^{-1} \times 552 \times 10^3\; kg = 5.41412\times 10^6\; N$ .

The magnitude of the net force on the rocket would be

$\begin{aligned}&\text{Thrust} - \text{Weight} \\ &= 7.61 \times 10^6\; \rm N - 5.41412\times 10^6\; N \\ &\approx 2.19 \times 10^6\; \rm N\end{aligned}$ .

Apply the formula $\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ to find the net force on the rocket. To make sure that the output (acceleration) is in SI units (meters-per-second,) make sure that the inputs (net force and mass) are also in SI units (Newtons for net force and kilograms for mass.)

$\begin{aligned}\displaystyle &\text{Acceleration} \\ &= \frac{\text{Net Force}}{\text{Mass}} \\ &= \frac{2.19 \times 10^6\; \rm N}{552 \times 10^3\; \rm kg} \\ &\approx \rm 3.98\; \rm m \cdot s^{-2}\end{aligned}$ .

6 0

3 years ago

The absolute temperature of a gas is t. in order to double the rms speed of its molecules, what should be the new absloute tempe

jenyasd209 [6]

The new absloute temperature should be 4t.

<h3>Temperature </h3>

The hotness of matter or radiation is expressed by the physical quantity known as temperature.

There are three different types of temperature scales: those, like the SI scale, that are defined in terms of the average translational kinetic energy per freely moving microscopic particle, like an atom, molecule, or electron in a body; those that solely depend on strictly macroscopic properties and thermodynamic principles, like Kelvin's original definition; and those that are not defined by theoretical principles but rather by useful empirical properties of particula.

Using a thermometer, one can gauge temperature. It is calibrated using different temperature scales, each of which historically defined itself using a different set of reference points and thermometric materials.

Learn more about temperature here:

brainly.com/question/15267055

#SPJ4

6 0

2 years ago

Is the lithosphere part of the mantle or the crust? Explain.

gavmur [86]

Answer:

Both

Explanation:

The lithosphere is part of both the crust and the mantle.

It is the surface layer of the earth and also the most rigid layer. It is formed by the crust and the outermost part of the mantle. It is divided into two types: continental lithosphere and oceanic lithosphere.

The oceanic lithosphere has an approximate thickness of 50 - 100km, and the continental olithosphere of 40 - 200km.

8 0

4 years ago

A car is driving northwest at v mph across a sloping plain whose height, in feet above sea level, at a point n miles north and e

coldgirl [10]

Refer to the diagram shown.

Given:
$h(n,e) = 1500 + 75n + 50e$

Define
$\hat{r} = unit \, vector \, along \, \vec{v} \\ \hat{i} = unit \, vector \, east \\ \hat{j} = unit \, vector \, north \\ \nabla \equiv \hat{i} \frac{\partial}{\partial e} + \hat{j} \frac{\partial}{\partial n}$

$\hat{r} = \frac{1}{ \sqrt{2} } (-\hat{i}+\hat{j} )$

Then the rate of change of h with respect to the vector v is
$\nabla h . \hat{r} = \frac{1}{\sqrt{2}}(50\hat{i} + 75\hat{j}).(-\hat{i}+\hat{j}) = \frac{1}{\sqrt{2}} (-50+75) =17.68$

Answer: 17.7 ft per mile

3 0

3 years ago