Answer:
The coefficient of rolling friction for the tire under low pressure is 0.0342.
Explanation:
Two bicycle tires are set rolling with the same initial speed of 4.00 m/s
Final speed of both the bicycle, speed is reduced by half is measured, v = 2 m/s.
Here,
Using third equation of motion as :
So, the coefficient of rolling friction for the tire under low pressure is 0.0342.
(a)
First of all, we need to calculate the acceleration of the person, by using the following SUVAT equation:
where
v = 0 is the final velocity
u = 20.0 m/s is the initial velocity
a is the acceleration
d = 1.00 cm = 0.01 m is the displacement of the person
Solving for a,
And the average force on the person is given by
with m = 75.0 kg being the mass of the person. Substituting,
where the negative sign means the force is opposite to the direction of motion of the person.
b)
In this case,
v = 0 is the final velocity
u = 20.0 m/s is the initial velocity
a is the acceleration
d = 15.00 cm = 0.15 m is the displacement of the person with the air bag
So the acceleration is
So the average force on the person is
Answer:
Meter (m)
Explanation:
The wavelenght of a light wave is a measure of the distance between two successive crests (or two successive troughs) of a light wave.
Since the SI units for the distance is the meter (m), then the SI unit for the wavelength is also the meter (m).
Wavelength is related to the frequency of the light wave by:
where
c is the speed of light
f is the frequency of the light