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Nady [450]
2 years ago
10

~~~15 POINTS~~~

Mathematics
1 answer:
REY [17]2 years ago
7 0
Let's call bicycles 'b' and unicycles 'u'
Note that bicycles have 2 tires, and unicycles have 1 tire.

We can make two equations:

b = u + 8
2b + 1u = 46

Solving the first equation for u, we get:

u = b - 8

Plug that equation into the second, and we get:

2b + (b - 8) = 46

Subtract 2b on both sides.

1(b - 8) = 46 - 2b

Basically, I used b and your question used n.

The correct answer is: D. 1(n - 8) = 46 - 2n.
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podryga [215]

Answer:

Suppose that G(X) = F(x+ 9). Which statement best compares the graph of

G(X) with the graph of F(x)?

O A. The graph of G(X) is the graph of F(x) shifted 9 units try the left.

B. The graph of G(x) is the graph of F(X) shifted 9 units down.

C. The graph of G(x) is the graph of F(x) shifted 9 units up.

D. The graph of G(X) is the graph of F(x) shifted 9 units to the right.

Step-by-step explanation:

Suppose that G(X) = F(x+ 9). Which statement best compares the graph of

G(X) with the graph of F(x)?

O A. The graph of G(X) is the graph of F(x) shifted 9 units try the left.

B. The graph of G(x) is the graph of F(X) shifted 9 units down.

C. The graph of G(x) is the graph of F(x) shifted 9 units up.

D. The graph of G(X) is the graph of F(x) shifted 9 units to the right.

6 0
2 years ago
Fraction word problems Your strip of paper represents one lap on a track. Three students ran a relay and took turns running equa
artcher [175]

Answer:

A quarter (\dfrac{1}{4}) of one lap of the track.

Step-by-step explanation:

Three students ran ran a relay and took turns running equal parts of the track.

The race was three-fourths of a lap long.

Let the length of one lap of the track=x

The length of the race=\frac{3}{4}x

Since each of the students ran equal part,

Length run by each student

=\dfrac{3}{4}x \div 3\\=\dfrac{3}{4}x X \dfrac{1}{3}\\=\dfrac{1}{4}x

Therefore, each student ran a quarter (\dfrac{1}{4}) of one lap of the track.

5 0
3 years ago
How to use order of operation in 20 divide by 4 multiply 5 = 1
I am Lyosha [343]
Use PEMDAS. 20/(4*5)=1
Multiplication before dividion
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3 years ago
To prove that ΔDEF ≅ ΔDGF by SSS, what additional information is needed?
FinnZ [79.3K]

Answer:

DE ≅ DG

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
19/258 = 21/?<br><br> help pls
Mashcka [7]

Answer:

<h3>285.15</h3>

Step-by-step explanation:

Given the expression;

19/258 = 21/x

We are to find the unknown value x;

Cross multiply;

19 * x = 258 * 21

19x = 5418

Divide both sides by 19;

19x/19 = 5418/19

x = 285.15

Hence the unknown value is 285.15

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2 years ago
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