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ZanzabumX [31]
3 years ago
12

Does 4/8 +7/8=11/16 or 11/8

Mathematics
2 answers:
ss7ja [257]3 years ago
5 0
That's easy it is 11/8 because 4+7=11 8 will be the same
deff fn [24]3 years ago
3 0
The answer would be 11/8 because 7+4=11 and then the denominator(8) will stay the same.
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A solid sphere is cut into 4 equal wedges the volume of each wedge is v=1/3r3 solve the volume for r
Dennis_Churaev [7]

Answer:

r = (3V/π)^1/3

Step-by-step explanation:

Given that :

Volume of a sphere = V = 4/3πr³

Dividing into 4

4/3 * 1/4 πr³ = 4/12πr³ = 1/3πr³

V = 1/3πr³

Cross multiply

3V = πr³

Divide both sides by π

3V/ π = πr³/ π

3V/ π = r³

Take the cube root of both sides

r = (3V/π)^1/3

6 0
3 years ago
Given: O is the midpoint of line MN<br> OM=OW<br> Prove: OW=ON
grigory [225]
Given:
O is the midpoint of line MN
OM = OW

To prove:  OW = ON

<u>Statement</u>                                 <u>Reason</u>
1> OM = OW  -------------------------> Given
2> OM = ON ---------------------------> O is the midpoint of line MN
                                                           i.e Point O bisects line MN
3> OM = OW --------------------------> From statement <1>
4> ON = OW  -------------------------> OM = ON (Statement <2>)
     OW = ON
              
                                                                    <u>proved!!</u>
   


6 0
3 years ago
Round off 9.999 to the nearest 10​
dlinn [17]

Answer:

the answer is 10 you round up a nine it keeps going to the end

6 0
2 years ago
What is the answer it's not factor
Helen [10]
It is a divisor
hope this helps

7 0
3 years ago
A TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 500
nekit [7.7K]

Answer:

0.903264

Step-by-step explanation:

Given that a TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 5000 hours of use is 0.03 for a type A circuit board, 0.04 for a type B circuit board, and 0.03 for a type C circuit board.

Let A' = the event that A fails, B' =  B fails and C'= C fails.

Probability that no circuit board fails = Prob (A'B'C')

= P(A')P(B')P(C')  (since A,B, C are independent, their complements are independent

= (1-0.03)(1-0.04)(1-0.03)

= 0.903264

8 0
3 years ago
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