(x^a)(x^b)=x^(a+b)
(ab)(cd)=(a)(b)(c)(d)
x^-m=1/(x^m)
(3y^-4)(2y^-4)=
(3)(y^-4)(2)(y^-4)=
(6)(y^-8)=
6/(y^8)
If there are only two colors (let's say blue and red), here's what can happen:
sock #1 is blue
#2 is either blue or red. If blue, it matches #1 and you have a pair.
if red, go to #3
#3-either blue or red. If blue, matches #1. If red, matches #2.
OR sock #1 is red... then just reverse the colors. Basically, if you have three things that can only be in two groups, then even if two of them are different, the last one has to match one of them.
The factorization if the given expression 128 + 2d³ is 2(64 + d³).
<h3>Factorization</h3>
128 + 2d³
There are two parameters in the expression;
The common factors between 128 and 2d³ is 2
So,
128 + 2d³
= 2(64 + d³)
Learn more about factorization:
brainly.com/question/25829061
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Its B
rise over run dictates that its 2/8 which simplifies to 1/4
and its at an upward angle from left to right therefore its positive.
Not sure if your trying to solve for x or v