Answer:
Ba(OH)₂ requires more H₂SO₄ to reach neutralization..
Explanation:
- At neutralization, acid neutralize base to form salt and water at equivalence.
- NH₄OH is neutralized by H₂SO₄ according to the reaction:
<em>2NH₄OH + H₂SO₄ → (NH₄)₂SO₄ + 2H₂O.</em>
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It is clear that every 2 mol of NH₄OH need 1 mol of H₂SO₄ to be neutralized.
- Ba(OH)₂ is neutralized by H₂SO₄ according to the reaction:
<em>Ba(OH)₂ + H₂SO₄ → BaSO₄ + 2H₂O.</em>
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It is clear that every 1 mol of NH₄OH needs 1 mol of H₂SO₄ to be neutralized.
<em>So, Ba(OH)₂ requires more H₂SO₄ to reach neutralization.</em>
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Answer:
Metals are on the <em>far left side</em> of the staircase, except for Aluminum, Germanium, <em>Stibium</em><em> </em>[<em>Antimony</em>], Polonium, and <em>Tennessine</em><em> </em>[<em>Ununseptium</em>], and non-metals are on the <em>far right side</em> of the staircase, except for Boron, Carbon, Silicon, Arsenic, Selenium, Tellurium, Astatine, and <em>Oganesson</em> [<em>Ununoctium</em>], The <em>Periodic Table of Elements</em> was created by the famous Russian inventor and chemist <em>Dmitri Mendeleev</em>.
* The boldfaced elements are what are known as metalloids.
I am joyous to assist you anytime.
<span>The answer is 200 mol of water.
The balanced reaction is 2(H2) + (O2) = 2(H2O)
The limiting reactant is O2 as it will be completely consumed first, before hydrogen gas. Hydrogen gas would need at least 105 mol oxygen gas to be consumed; in excess of the 100 mol O2.
Looking at the stoichiometric coefficients, the ratio between water and oxygen is 2:1.
Therefore, the water produced would be 200 moles.</span>
