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VashaNatasha [74]

3 years ago

15

There were 16 dogs in line for the dog show parade. Popsie the poodle is the 12th dog in line. How many dogs are ahead of her? H

ow many dogs are behind her? Draw a picture to help you find the answers.

2 answers:

WARRIOR [948]3 years ago

6 0

There is 11 in front and 4 behind popsie! ;)

zysi [14]3 years ago

5 0

There are 4 in front of her and 11 behind her.

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WITCHER [35]

Answer:

<em>y = - x + 6 </em>

Step-by-step explanation:

<em>--</em><em> </em>Rhombus diagonals <u><em>are perpendicular and bisect</em></u> each other.

<em>--</em><em> </em>A( $x_{1}$ , $y_{1}$ ) and B( $x_{2}$ , $y_{2}$ )

Coordinates of <u><em>the midpoint</em></u> of a segment AB are

( $\frac{x_{1} +x_{2} }{2}$ , $\frac{y_{1} +y_{2} }{2}$ )

and <u><em>formula of a slope</em></u> of the line segment AB is

m = $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

<em>-- </em>If AB ⊥ CD then $m_{AB}$ × $m_{CD}$ = - 1

<em>-- </em><u><em>Slope-point of linear equation</em></u> is

y - $y_{1}$ = m( x - $x_{1}$ )

~~~~~~~~~~~~~~~~

M(0, 2)

T(4, 6)

$m_{MT}$ = $\frac{6-2}{4-0}$ = 1

$m_{AH}$ = - 1

Coordinates of the intersection of the diagonals are ( $\frac{4+0}{2}$ , $\frac{6+2}{2}$ ) = (2, 4)

y - 4 = - 1(x - 2)

<em>y = - x + 6</em> <u><em>is slope-intercept form of the diagonal AH</em></u>

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andrew-mc [135]

The answer will be Y=20

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Answer:

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