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tigry1 [53]
3 years ago
8

A 12 ft ladder is placed 5 feet from a building. Approximately how high does the ladder reach? Round to the nearest tenth, if ne

cessary.
Mathematics
1 answer:
lisov135 [29]3 years ago
4 0

Answer:

10.9 feet

Step-by-step explanation:

12^2 = 5^2+h^2

144 = 25 + h^2

-25 -25

h^2 = 119

h = square root 119

h = 10.9 ft

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2)

\frac{12x + 11}{x^2 +x - 6}

=\frac{12x + 11}{x^2 +3x-2x - 6}

=\frac{12x + 11}{x(x +3) -2(x +3)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{12x + 11}{(x +3) (x - 2)}

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\therefore 12x + 11 = A(x-2)+B(x+3)

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\therefore 12x + 11 = (A+B) x-2A+3B

Equating like terms on both sides:

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Solving equations (1) & (2), we find:

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Therefore, x =155

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