All categories

3 years ago

What is the gcf of 21 30 and 44what is the gcf of 21 , 30 , and 44?

Mathematics

2 answers:

Bond [772]3 years ago

5 0

The GCF= 1
i hope i helped

erastovalidia [21]3 years ago

3 0

Answer:

GCF = 1

Step-by-step explanation:

You might be interested in

Please help me!!!!!!!!!!!

Iteru [2.4K]

The point where the lines intersect.
this case (0,6)

5 0

2 years ago

Read 2 more answers

PLEASE HELP! Need answer fast

kondaur [170]

Answer:

Step-by-step explanation:

Because if you look closely you will be able to tell which answer it is by looking at the way the shape formed andjust breakaprt the shape .

6 0

1 year ago

I need help finding the area

aniked [119]

<h3>Given :</h3>

Base of triangle = 7 yd
Height of triangle = 10 yd

$\\ \\$

Area of triangle

$\\ \\$

We know:-

When base and height of triangle is given we use this formula:

$\bigstar \boxed{ \rm Area \: of \: triangle = \frac{base \times height}{2} }$

$\\ \\$

So:-

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{base \times height}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 10}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times2 }{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times\cancel2 }{\cancel2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times1 }{1} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5$

$\\ \\$

$\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2} \\$

$\\ \\$

$\therefore \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} { \red{\bf{yd} }^{ \red2} }}$

$\\ \\$

$\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}$ ]

7 0

2 years ago

Custumers of a phone company can choose between two service plans for long distance calls. The first plan has a $9 monthly fee a

saul85 [17]

The answer is 350.
<em>
m= minutes</em>

Plan 1: 9+0.13<em>m</em>
Plan 2: 23+0.09<em>m</em>

9+0.13<em>m</em> = 23+0.09<em>m</em>
-9 -9
0.13<em>m</em> = 14+0.09<em>m</em>
-0.09<em>m</em> -0.09<em>m</em>
0.04<em>m</em>= 14
14÷0.04= 350
<em>m</em>= 350

3 0

3 years ago

Read 2 more answers

Sharon and Jacob started at the same place. Jacob walked 3 m north and then 4 m west. Sharon walked 5 m south and 12 m east. How

Ilya [14]

Consider the coordinate plane:

1. The origin is the point where Sharon and Jacob started - (0,0).

2. North - positive y-direction, south - negetive y-direction.

3. East - positive x-direction, west - negative x-direction.

Then,

if Jacob walked 3 m north and then 4 m west, the point where he is now has coordinates (-4,3);
if Sharon walked 5 m south and 12 m east, the point where she is now has coordinates (12,-5).

The distance between two points with coordinates $(x_1,y_1)$ and $(x_2,y_2)$ can be calculated using formula

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.$

Therefore, the distance between Jacob and Sharon is

$D=\sqrt{(12-(-4))^2+(-5-3)^2}=\sqrt{16^2+8^2}=\sqrt{256+64}=\sqrt{320}=8\sqrt{5}\approx 11.18\ m.$

7 0

3 years ago