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3 years ago

Solve the following equation:m - m-1/2 = 1 - m-2/3

Mathematics

1 answer:

grigory [225]3 years ago

3 0

Answer:

m = $\frac{7}{5}$

Step-by-step explanation:

m - $\frac{m-1}{2}$ = 1 - $\frac{m-2}{3}$

Multiply through by 6 ( the LCM of 2 and 3 ) to clear the fractions

6m - 3(m - 1) = 6 - 2(m - 2) ← distribute parenthesis on both sides

6m - 3m + 3 = 6 - 2m + 4 , that is

3m + 3 = - 2m + 10 ( add 2m to both sides )

5m + 3 = 10 ( subtract 3 from both sides )

5m = 7 ( divide both sides by 5 )

m = $\frac{7}{5}$

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Arisa [49]

The two rational expressions will be; (x + 2)/(x² - 36) and 1/(x² + 6x)

<h3>How to simplify Quadratic Expressions?</h3>

We want to determine the two rational expressions whose difference completes the equation.

The two rational expressions will be;

(x + 2)/(x² - 36) and 1/(x² + 6x)

Now, this can be proved as follows;

Step 2 [(x + 2)/(x² - 36)] - [1/(x² + 6)]

= [(x + 2)/(x + 6)(x - 6)] - [1/(x(x + 6)]

Step 3; By subtracting, we have;

[x(x + 2) - (x - 6)]/[x(x + 6)(x - 6)]

Step 4; By further simplification of step 3, we have;

[x² + x + 6]/[x(x-6)(x + 6)]

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1 year ago

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Yakvenalex [24]

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Step-by-step explanation:

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3 years ago

Given 2 lines cut by a transversal, what would the m<7 have to be if m <4=85 for the lines to be parallel and what is the

nlexa [21]

Answer:

85º

Step-by-step explanation:

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2 years ago

In triangle ABC, a = 9, c = 5, and angle B = 120°. Find the measure of angle A to the nearest degree. Show your work.

slamgirl [31]

<u>Answer:</u>

Angle A = 39°

<u>Step-by-step explanation:</u>

We are given that there is a triangle ABC where a = 9, c = 5 and angle B = 120° and we are to find the measure of angle A.

But first we need to find the side b using the law of cosine:

$b^2 = a^2 + c^2- 2a*c*cos(120)$

$b^2 = 81 + 25 - 2*9*5*(-0.5)$

$b=\sqrt{151}$

Now finding angle A using law of cosine:

$cos(A) = \frac{b^2+c^2-a^2}{2b*c}$

$cos(A) = \frac{151+25-81}{2*12.29*5}$

$cos A=0.7730$

$A=39.38$

Therefore, the measure of angle A = 39°.

7 0

3 years ago

Read 2 more answers

Pls can someone help me<br><img src="https://tex.z-dn.net/?f=%20log10%20%5Csqrt%7B36%7D%20%20%2B%20%20%20%20log10%20%20%5Csqrt%7

Firlakuza [10]

Answer:

$= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

Step-by-step explanation:

Given the expression $log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\$

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

$log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

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3 years ago

Solve the following equation:m - m-1/2 = 1 - m-2/3​

Solve the following equation:m - m-1/2 = 1 - m-2/3