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VLD [36.1K]
3 years ago
6

Which is a right triangle formed using a diagonal through the interior of the cube?

Mathematics
2 answers:
garri49 [273]3 years ago
6 0

Answer:

<u>The answer is C) triangle DGH</u>

Step-by-step explanation:

I took the test on E d g e n u i t y, and I honestly just guessed C), <u>AND IT WAS RIGHT</u>

so I guess the answer is <u>C) triangle DGH </u>

Have a wonderful rest of your day!! \(^u^\)

UkoKoshka [18]3 years ago
4 0

Answer:

c

Step-by-step explanation:

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Seven friends each bought a movie ticket for $14.95, popcorn for $6.99, and a drink for $2.25. How much did the friends spend in
VLD [36.1K]

Answer:

  $169.33

Step-by-step explanation:

Each of the friends spent ...

  $14.95 +6.99 +2.25 = $24.19

The seven friends together spent ...

  7($24.19) = $169.33

5 0
2 years ago
A basket holds at most 14 pounds of apples and oranges
Helen [10]
A.

B and C are wrong because x is more than or equal to 3.

D is wrong because y is the weight of oranges and cannot be negative.
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3 years ago
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Expression 1:
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1. Did it mentally think it’s 16. Make sure to yield to order of operations.
2. Because none of the operations are multiplication or division, parenthesis can be put anywhere that isn’t between exponents and it will yield 22.
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3 years ago
an art teacher has 1 1/2 pounds of red clay and 3/4 pound of yellow clay.The teacher mixes the red clay and yellow clay together
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7 0
3 years ago
The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle
Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

|AB|=\sqrt{(-1--5)^2+(8-6)^2}

|AB|=\sqrt{16+4}

|AB|=\sqrt{20}

The length of AD is

|AD|=\sqrt{(-1--5)^2+(6-4)^2}

|AD|=\sqrt{16+4}

|AD|=\sqrt{20}

The length of BC is:

|BC|=\sqrt{(-1-3)^2+(8-6)^2}

|BC|=\sqrt{16+4}

|BC|=\sqrt{20}

The length of CD is

|CD|=\sqrt{(-1-3)^2+(6-4)^2}

|CD|=\sqrt{16+4}

|CD|=\sqrt{20}

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB=\frac{8-6}{-1--5}=\frac{1}{2}

Slope of BC =\frac{8-6}{-1-3}=-\frac{1}{2}

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be  a square. It is a rhombus

7 0
3 years ago
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