All categories

3 years ago

Rounding whole number which number could round to 80,600 80,532 80,549 80,617 80, ,651

Mathematics

1 answer:

Burka [1]3 years ago

6 0

Answer:

80,617

Step-by-step explanation:

the 1 in the tens place puts the number back down to 600

You might be interested in

Greg is traveling north on a road while Peter is traveling south on the same road. They pass by each other at noon, Greg driving

max2010maxim [7]

40x+30x=315

70x=315

315/70= 4.5 hours

12:00 noon + 4.5 hours = 4:30 pm

5 0

3 years ago

Solve the following question algebraically, show your work<br><br> 13 + w/7 <-(fraction) = -18

evablogger [386]

Solve for w: by simplifying both sides of the equation, then isolating the variable.

w=-217

Work: 1. Subtract 13 from both sides (w/7 = -18 - 13), 2.Simplify -18-13 to -31 (w/7=-31), 3.Multiply both sides by 7 (w = -31 * 7), 4. Simplify 31*7 to 217 (w=-217)

8 0

3 years ago

Mrs. Humble is filling bags with peanuts to give as gifts. Each bag will contain 1 and 3 over 4 pounds of peanuts. The peanuts c

DerKrebs [107]

Answer:

$8.75

Step-by-step explanation:

STEP TO TAKE TO DETERMINE THE ANSWER

Multiply 13/4 pounds by the cost of one pound of peanut. To do this, convert 13/4 to an improper fraction and then multiply it by $5

$1\frac{3}{4}$ = $\frac{7}{4}$

$\frac{7}{4}$ × 5 = $\frac{35}{4}$ = $8\frac{3}{4}$ = $8.75

5 0

3 years ago

Graph - 2x + 4y = 16 using<br> intercepts.

castortr0y [4]

Answer:

y intercept is -1/2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click

Sergeeva-Olga [200]

Answer:

A. $\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

B. $\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

Step-by-step explanation:

Given that:

An investment of Amount = $8000

earns at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A) Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

$A = Pe^{rt}$

where;

$A = (8000) \ e ^{0.7t}$

The instantaneous rate of change = $\dfrac{dA}{dt}$

$\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )$

$= 8000 \dfrac{d}{dt}e^{0.07 \ t}$

$\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}$

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 2 years; the instantaneous rate of change is:

$\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}$

$\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

$12000 = (8000)e^{0.07 \ t}$

$\dfrac{12000 }{8000}= e^{0.07 \ t}$

$1.5= e^{0.07 \ t}$

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 5.79

$\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}$

$\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

7 0

3 years ago