1.42 because you subtract 10 from the price
Answer:
4x+5y-34=0
Step-by-step explanation:
The slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.
My goal is to put in in this form first. Then I will aim to put it in general form, ax+by+c=0.
So let's give it a go:
m is the change of y over the change of x.
To compute this I'm going to line my points up and subtract vertically, then put 2nd difference over 1st difference. Like this:
( 1 , 6)
-(6 , 2)
----------
-5 4
So the slope is 4/-5 or -4/5.
So m=-4/5.
Now we are going to find b given y=mx+b and m=-4/5 and we have a point (x,y)=(1,6) [didn't matter what point you chose here].
6=-4/5 (1)+b
6=-4/5 +b
Add 4/5 on both sides:
6+4/5=b
30/5+4/5=b
34/5=b
So the y-intercept is 34/5.
The equation in slope-intercept form is:
y=-4/5 x + 34/5.
In general form, it is sometimes the goal to make all of your coefficients integers so let's do that. To get rid of the fractions, I'm going to multiply both sides by 5. This clears the 5's that were on bottom since 5/5=1.
5y=-4x+34
Now add 4x on both sides:
4x+5y=34 This is standard form.
Subtract 34 on both sides:
4x+5y-34=0
5 + 6 hahahahaha hahhahhahaha
The answer is 7 good luck
You must develop a cost function C(x) and then minimize its value.
How much dwill the glass cost? It's $1 per sq ft, and the total area of the glass is 4(xh), where x is the length of one side of the base and h is the height of the tank. The area of the metal bottom is x^2, which we must multiply by $1.50 per sq ft.
This cost function will look like this: C(x) = 4($1/ft^2)xh + ($1.50/ft^2)x^2
but we know that (x^2)h= 6 cu ft, or h = (6 cu ft) / (x^2). Subst. this last result into the C(x) equation, immediately above:
C(x) = 4($1/ft^2)x[6 ft^3 / x^2] + ($1.50/ft^2)x^2
Let's focus on the numerical values and ditch the units of measurement for now:
C(x) = 4x(4/x^2) + 1.50x^2, or
C(x) = 16/x + 1.5x^2
Differentiate this with respect to x:
C '(x) = -16 / x^2 + 3 x
Set this equal to 0 and solve for x: -16/x^2 = -3x, or 16 = 3x^3
Then x^3 = 16/3, and x = 5 1/3 ft. We already have the formula
(x^2)h= 6 cu ft, so if x = 5 1/3, or 16/3, then (16/3)^2 h = 6, or
h = 6 / [16/3]^2.
h = 6 (9/256) = 0.21 ft. While possible, this h = 0.21 ft seems quite unlikely.
Please work through this problem yourself, making sure you understand each step. If questions arise, or if you find an error in my approach, please let me know.
Once again:
1. Write a formula for the total cost of the material used: 4 sides of dimensions xh each, plus 1 bottom, of dimensions x^2. Include the unit prices: $1 per square foot for the sides and $1.50 per square foot for the bottom.
2. Differentiate C(x) with respect to x.
3. Set C '(x) = 0 and solve for the critical value(s).
4. Calculate h from your value for x.
5. Write the dimensions of the tank: bottom: x^2; height: h
