Answer:
- Number of calories in burger = 620 calories
- Number of calories in hotdog = 400 calories
Step-by-step explanation:
Number of calories in burger = x
Number of calories in hotdog = y
y = x - 220
x + 2y = 1,420
Substitution:
x + 2 * (x - 220) = 1,420
x + 2x - 440 = 1,420
3x = 1,420 + 440
x = 1,860 / 3
x = 620 calories
y = x - 220
= 620 - 220
= 400 calories
11 bottles are needed to fill a 16 liter jug
<em><u>Solution:</u></em>
Given that, there is a 16 liter jug
There are 
liters of bottle
<em><u>Let us first convert the mixed fraction to improper fraction</u></em>
Multiply the whole number part by the fraction's denominator.
Add that to the numerator.
Then write the result on top of the denominator.
Thus the bottle is of 1.5 liter
We have to find the number of 1.5 liter bottles needed to fill 16 liter jug
Divide 16 by 1.5 to get result
Thus 11 bottles are needed to fill a 16 liter jug
Answer:
(1, -1)
Step-by-step explanation:
we isolate y in the first equation
2x+y=1
-2x. -2x
y=1-2x
and now we fill y into second equation
4x-2(1-2x)=6
4x-2+4x=6
8x-2=6
+2 +2
8x=8
/8 /8
x=1
and now to find y we insert x
2(1)+y=1
2+y=1
-2. -2
y= -1
hopes this helps
Answer:
Step-by-step explanation:
All that we have to do is add the 3 and 5 so it's basically like combining like terms. So the first blank is 8.
Now we add the x and the 5x which is 6x, all we're doing is adding the x's.
Now we do add the two negative 10 and 7. So what is -10 + - 7 we add them normally but we'll still have the negative in front of them. So it's -17.
Original coordinates of the points:
A (8,15) ; B (12,13) ; C (8,10)
Dilated scale factor of 3.
A ⇒ 3x = 3(8) = 24 ; 3y = 3(15) = 45 ⇒ A' (24,45)
B ⇒ 3x = 3(12) = 36 ; 3y = 3(13) = 39 ⇒ B' (36, 39)
C ⇒ 3x = 3(8) = 24 ; 3y = 3(10) = 30 ⇒ C' (24, 30)
The given image forms a right triangle. So, I'll get the short leg and long leg of the right triangle to solve for the hypotenuse, length of CB.
Short leg: y value of B and C
39 - 30 = 9
Long leg: x value of B and C
36 - 24 = 12
a² + b² = c²
9² + 12² = c²
81 + 144 = c²
225 = c²
√225 = √c²
15 = c
The length of CB is 15 units.
