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SOVA2 [1]
3 years ago
13

State two reasons why the large ground finch and sharp-billed ground finch could live on the same island but not compete for foo

d, even though they both eat mainly plant food.

Biology
2 answers:
enyata [817]3 years ago
6 0
One reason is that the two kinds of birds live in two different types of environments and also the sharp billed ground finch does not just it plant matter. It feast on the blood of bigger sea birds. This is an adaptation that it has so it does not have to eat plant matter and compete for food
LuckyWell [14K]3 years ago
6 0

Answer:

  • They eat different plants.
  • They live in different regions of the island.

Explanation:

Sharp-billed are small birds, measuring at most centimeters. They are brightly colored birds that sing frequently, which makes them very coveted by hunters and bird watchers.

There are different types of sharp-billed, but all types have characteristics in common, in addition to being herbivorous animals.

It is possible that all types of sharp-billed live peacefully in the same area, without causing competition for food. This is because each type of sharp-billed has a different preference in relation to the plant that is being consumed, even if they share the preference for the same plant, competition can be avoided if each type of sharp-billed lives in a different region, or if they eat at different times.

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Fittoniya [83]

Answer: 1/16, or approximately 6.25% (see explanation below)

Explanation:

Answering this question requires two steps.

First, we need to figure out the probability that this couple will have a child with albinism in the first place. We know the following:

- Both parents are unaffected.

- The couple has already had one affected child.

- Albinism follows an autosomal recessive inheritance pattern.

Let ( M = normal gene ) and ( m = mutated gene ). Since the condition is recessive, the affected child can be assumed to have a “mm” genotype. Barring the possibility of a de novo mutation (which are assumed to be rare), the affected child must have inherited one ”m” allele from each parent. Since both of them are unaffected, however, we can assume that they are both carriers (genotype “Mm”). In conclusion, 1/4 of their offspring (25%) <em>for any given pregnancy</em> may be expected to have albinism. See the resulting Punnett square:

<u>       |      M    |      m   </u>

<u>M    |    MM   |    Mm  </u>

<u>m    |    Mm   |    mm  </u>

Note that the question asks about the probability that not one but two consecutive births result in affected children. Since it can be assumed that both events are independent (meaning: the outcome of a pregnancy does not influence the outcome of following ones), we may apply the rule of multiplication for probabilities. The final answer is therefore 1/4 * 1/4 = 1/16.

7 0
3 years ago
Which of the following statements is correct?
Keith_Richards [23]

Answer:

The statement that is correct is that all cells have the same genes, but different genes are active in different cells.

Explanation:

Differentiation or specialization is a function that cells possess and is what allows them to have different types of cells and tissues.

Cell differentiation depends on genetic regulation, a mechanism that determines the specific genes that are expressed in a cell or tissue type.

All cells contain the same DNA, which is organized into chromosomes and contain the genes that determine specific characteristics. <u>There is cell differentiation because some genes can be expressed and others are suppressed, all due to genetic regulation</u>.

The other choices are wrong because:

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No, cladograms deal with living species.
8 0
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Answer:

A

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Explanation:

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