It's kinda like using variables, but shapes in their place. Let's set the circle to x, the triangle to y, and the square to z. Now the equations say x+(y+z)=13, (y+z)=8, and x+y=7. First thing we can do it plug 8 into the first equation for y+z, getting x+8=13. Subtract 8 to both sides and x (or circle) equals 5. Plug 5 into the last equation, x+y=7 to solve for y, getting 5+y=7. Subtract 5 to both sides and y (or triangle) equals 2. Finally, plug two in for y in y+z=8, getting 2+z=8. Subtract 2 from both sides and z (or square) equals 6. Hope I've explained it clearly!!
-7-1/2-5 because to solve, you do y2-y1/x2-x1
So you get -6/-3, which equals 2
SLOPE IS 2
86 and 95; 8+6=14 and 9+5 also =14. The tens value for both of these numbers are also higher than their ones place.
The formula of a distance between two points:
We have the points (-3, 3) and (5, 0).
Substitute the coordinates of the points to the formula:
