Answer:
As we know:
A nickle is worth 5 cents.
A dime is worth 10 cents.
A quarter is worth 25 cents.
Here is what Robert had:
Number of nickles (a)
Number of dimes (b)
Number of quarters (c)
Here is assumption:
5a + 10b + 25c = 850
a = 3b
c = b + 10
=> 5(3b) + 10b + 25(b + 10) = 850
=> 50b + 250 = 850
=> 50b = 600
=> b = 600/50 = 12
=> a = 3b = 3 x 12 = 36
=> c = b + 10 = 12 + 10 = 22
=> Number of nickles: 36
=> Number of dimes: 12
=> Number of quarters: 22
Hope this helps!
:)
Answer:
16x^2 - 49y^2 = 784
Step-by-step explanation:
as we know that this is the standard equation of hyperbola bcz 1 coordinate of vertices is 0.
since in vertices x coordinate is present and y coordinate is 0 so Tranverse axis of hyperbola is along x axis .
vertices in general = (a,0) and (-a,0)
vertices given = ( 7,0) and (-7 , 0)
so a=7
similarly
co vertices in general = ( 0 , b) and ( 0 , -b)
co vertices given = ( 0, 4) and (0 , -4)
so,
b= 4
now equation for x axis is:
(x2/a2) - ( y2/b2) = 1
by putting values we observe the ans is
16x^2 - 49y^2 = 784
First of all we are going to take $7.25 and multiply it by 3 here is the math
7.25 x 3 = 21.75
so this means he makes 21.75 dollars a day.
since there are 365 days a year. Now i'm not saying he worked every single day but the question does not say other wise
so we would take 21.75 and multiply it by 365 heres the math
21.75 x 365 = 7,938.75
this means he makes 7,938.75 dollars a year!!
your welcome
merry christmas
Every triangle angles add up to 180.
So because one angle is 90 degrees you would subtract it from 180 to get 90 and then divide it by two which is 45 degrees.
Hope this helps, have a nice day! :)
Answer:
The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).
