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Inessa [10]
3 years ago
11

The vertices of a quadrilateral in the coordinate plane are known. How can the perimeter of the figure be found?

Mathematics
2 answers:
AlekseyPX3 years ago
5 0

Answer:

Use the distance formula to find the length of each side, and then add the lengths.

Step-by-step explanation:

We are given the vertices of a quadrilateral in the coordinate plane.

We have to find the perimeter of the figure.

For doing so, we have to find the length of all the sides of a quadrilateral

The length of a line segment joining points (x1,y1) and (x2,y2) is given by the distance formula:  \sqrt{(x2-x1)^2+(y2-y1)^2}

after finding length of all the sides, we add the length of each side to get the perimeter.

Hence, the correct option is:

Use the distance formula to find the length of each side, and then add the lengths.

vladimir2022 [97]3 years ago
5 0
You can find the distance of each side and add up the values.
Your answer is A.
gimme brainliest plzzzz thank u


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he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
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Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

P(X

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

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b) between 8 and 9 minutes:

P(8< X' <9) =[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

NORMSDIST(6.366)-NORMSDIST(-1.47)

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

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2 years ago
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