Answer:
Width = 18, height = 3
Or
Width = 6, height = 9
Step-by-step explanation:
Complete question
( A piece of sheet metal 24 inches wide is bent to form a gutter as shown in the picture below, if the cross sectional area is 54 square inches, find the depth of the gutter).
X = width, Y = height
X - 2y = 24........ equation i
X = 24 - 2y.......... equation ii
Area = xy
54 = xy........ equation iii
Put equation ii into equation iii
54 = (24 - 2y) * y
54 = 24y - 2y²
2y² - 24y + 54 = 0........ equation iv
Solving equation iv using quadratic methods,
Factors = (y-3), (y-9)
(Y-3)(y-9) = 0
y = 3 or y = 9
Substitute y = 3 or y = 9 into equation ii
X = 24 -2(3) = 18 or x = 24 - 2(9) = 6
If Width = 18, height = 3
Or
Width = 6, height = 9
The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are
The function is given as:
f(x) = 3x^6 + 4x^3 -2x^2 + 4
The leading coefficient of the function is:
p = 3
The constant term is
q = 4
Take the factors of the above terms
p = 1 and 3
q = 1, 2 and 4
The possible zeros are then calculated as:
So, we have:
Expand
Solve
Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are
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