Solution :
Faulty electrical connects = P(A) = 0.80
Mechanical defects = P(B) = 0.92
Mechanical defects are related to loose keys = P(C/B) = 0.27
Improper assembly = P(D/B) = 0.73
Defective wires = P(E/A) = 0.35
Improper connections = P(F/A) = 0.13
Poorly welded wires = P(G/A) = 0.52
Now, the probability due to loose keys = 0.27 x 0.92 = 0.2484
Improperly connected = 0.13 x 0.80 = 0.1040
Poorly welded wires = 0.52 x 0.80 = 0.4160
So, the probability that a failure is due to improperly connected or poorly welded wires = 0.1040 + 0.4160
= 0.5200
Answer:
X[bar]= 115
Step-by-step explanation:
Hello!
Every Confidence interval to estimate the population mean are constructed following the structure:
"Estimator" ± margin of error"
Wich means that the intervals are centered around the sample mean. To know the value of the sample mean you have to make the following calculation:
![X[bar]= \frac{Upper bond + Low bond}{2}](https://tex.z-dn.net/?f=X%5Bbar%5D%3D%20%5Cfrac%7BUpper%20bond%20%2B%20Low%20bond%7D%7B2%7D)
![X[bar]= \frac{115.6+114.4}{2}](https://tex.z-dn.net/?f=X%5Bbar%5D%3D%20%5Cfrac%7B115.6%2B114.4%7D%7B2%7D)
= 115
Since both intervals were calculated with the information of the same sample, you can choose either to calculate the sample mean.
I hope it helps!
Answer:
164
Step-by-step explanation:
The formula is *4
41*4=164
Answer: f(2)=5
Step-by-step explanation:
f(2)=2(2)+1=5
f(2)=5
