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QveST [7]
3 years ago
12

Help pls I’ll make you brainliest if u get it right

Mathematics
1 answer:
Tomtit [17]3 years ago
4 0

Answer:

2

Step-by-step explantion:

This isnt following by the formula but if you look at the pattern ir adds 2 every time

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HELP PLEASEEEEEE NO LINKS PLEASE 20PTS!!!!
nevsk [136]

Answer:

x = 5

Step-by-step explanation:

3x + 11 = 26

3x = 15

x = 5

5 0
3 years ago
20 POINTS! The following graph shows the amount of money Jonah earns when he babysits for the family who lives next door. Based
katrin2010 [14]

Answer:

The equation e = 4 h can be used to describe this situation.

Jonah earns $20 to babysit for 5 hours.

Step-by-step explanation:

When Jonah babysits one hour, he earns $7.50.

looking at the graph we see at 1 hour he earns 4 dollars false

The equation e = 4 h can be used to describe this situation.

The slope is 4   so y = 4x   e = 4h  would also work   true

Jonah earns $20 to babysit for 5 hours.

Using our equation from above

e = 4*5 = 20   true

The number of hours Jonah works depends on how much he earns.

This would be false

The dependent variable is on the y axis.  The amount he earns depends on how much he works

3 0
3 years ago
Which is equivalent ratio to 4:5 (select all that are true)
Sever21 [200]
It is b only b I think sorry If I am wrong have a good day
8 0
3 years ago
Use the line plot below to answer the following questions when x=9​
loris [4]

Answer:

8 x + 3 = 75

9 x - 6 = 75

5 x + 5 = 50

Step-by-step explanation:

8 x + 3

8 (9) + 3

72 + 3

75

---------------------------

9 x - 6

9 (9) - 6

81 - 6

75

---------------------------

5 x + 5

5 (9) + 5

45 + 5

50

3 0
3 years ago
Write the point-slope form of the line that passes through (5,5) and is perpendicular to a line with a slope of 1/4 include all
amid [387]

<u>Answer:</u>

The point-slope form of the line that passes through (5,5) and is perpendicular to a line with a slope of \frac{1}{4} is 4x + y -25 = 0

<u>Solution:</u>

The point slope form of the line that passes through the points \left(x_{1} y_{1}\right) and perpendicular to the line with a slope of “m” is given as  

\bold{y-y_{1}=-\frac{1}{m}\left(x-x_{1}\right)} ---- eqn 1

Where “m” is the slope of the line. x_{1} \text { and } y_{1} are the points that passes through the line.

From question, given that slope “m” = \frac{1}{4}

Given that the line passes through the points (5,5).Hence we get

x_{1}=5 ; y_{1}=5

By substituting the values in eqn 1 , we get the point slope form of the line which is perpendicular to the line having slope \frac{1}{4}can be found out.

y - 5 = -4(x - 5)

y - 5 = -4x + 20

on simplifying the above equation, we get

y - 5 + 4x -20 = 0

4x + y - 25 = 0

hence the point slope form of given line is 4x + y - 25 = 0

3 0
3 years ago
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