Answer:
270 Degree Rotation
Step-by-step explanation:
When rotating a point 270 degrees counterclockwise about the origin our point A(x,y) becomes A'(y,-x). This means, we switch x and y and make x negative.
sinx-✓(1-3sin2x)=0
-✓(1-3sin2x)=-sinx
apply squared both sides
(-✓(1-3sin2x)^2=(-sinx)^2
1-3sin2x=sin2x
collect like terms
-3sin2x-sin2x+1=0
-4sin2x+1=0
-4sin2x=-1
devide both sides by -4
sin2x=-1/-4
sin2x=0.25
sinx*sinx =0.25
[sinx]^2 = 0.25
apply square root both sides
<h2>✓(sinx)2 = ✓0.25</h2>
<h2>sinx=0.5</h2><h2> </h2><h2>x=sin^-(0.5)</h2>
<h2>x=30°</h2>
<h3>check quadrant where sin is positive, sin is +ve in second quandrant</h3>
180-x= Theta(X)
180-30=X
X=150°
therefore, all angles for sinx -✓(1-3sin2x)=0 are (X= 30° and 150°)
Answer:
c:8
Step-by-step explanation:
10/25 = r/20
25r = 200
25 25
r = 8
Answer:
sin(arccos(-4/√25)) = 0.6
Step-by-step explanation:
The expression you want to evaluate is
sin(arccos(-4/√25))
= sin(arccos(-4/5))
We place this expression into a calculator and get the result
arccos(-4/5) = 2.498 rads = 143.1°
then
sin(143.1°) = 3/5
sin(143.1°) = 0.6
sin(arccos(-4/√25)) = 0.6