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3 years ago

5

For a class trip, the teachers would like to have one adult for every ten students. There are 190 students on the trip. How many

adults should go on the trip?

1 answer:

coldgirl [10]3 years ago

6 0

You can solve this problem with the following

$\frac{1}{10} = \frac{a}{190}$
$10a = 190$
$a = 19$

There should be 19 adults on the trip.

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3 years ago

Solve the triangle A=21 C=105 c=5

gregori [183]

Answer:

Granted that uppercase letters are the angles measurements and lowercase letters are the side lengths. I also was unable to round as I don't know to what decimal you need to round to.

First to find the measure of angle B, we must subtract A and C from 180

$180-21-105=54$

B=54

Next, we can use the law of sines in order to find the measures of a and b

As a reminder, The law of sines is

$\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}$

First, lets solve for b

$\frac{b}{sin54}=\frac{5}{sin105} \\\\b=\frac{(5)sin54}{sin105}\\\\b=4.187780119$

Next lets solve for a

$\frac{a}{sin21}=\frac{5}{sin105} \\\\a=\frac{(5)sin21}{sin105}\\\\a=1.85504901$

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3 years ago

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Fofino [41]

Answer:

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