3 years ago

Help me problem in photo

Mathematics

1 answer:

Blababa [14]3 years ago

3 0

B and D because a- (-b)= a+b

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Determine whether the improper integral converges or diverges, and find the value of each that converges.

Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

$u=x$ $dv=e^(2x)\cdot{dx}$

$du=dx$ $v=2\cdot{e^(2x)}$

$\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du$

$\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx$

$\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C$

We can therefore determine that if x tends to 0 the limit is -1

$\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1$

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Step-by-step explanation:

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adell [148]

Answer:

y = $(x - 2)^{2}$

Step-by-step explanation:

the graph shows the vertex is (2,0); which means it is

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A wooden plank of length x is cut into 8 sections such that each section is at most 2 1/2 meters long. What is the length of the

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You would do 2.5*8 which equals 20. x=20

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