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Morgarella [4.7K]
3 years ago
12

Calvin wants to know the proportion of students at his school who plan to

Mathematics
1 answer:
tester [92]3 years ago
7 0
The answer is b. Let me know if you need an explanation
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The function y = -15 +2100 can be used to model the height, y, of a parachute jumper x seconds after she jumps from an airplane.
Aleks04 [339]
Did you mean to put a x after -15?
7 0
2 years ago
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We will use the values off(x) at the points 0.0,0.2,0.4,0.6,0.8. Generate the data set beforeyou start the numerical integration
leva [86]

Answer:

Check attachment for complete question and answer

8 0
2 years ago
Does the point (0, 0) satisfy the equation y = 9x?
miskamm [114]

Answer:

yes it does

Step-by-step explanation:

because the equation y=9x does not have a y-intercept (all slopes come in the form y=mx+b -- it can be written differently though) and since there is no 'b' that means the y-intercept is 0. So whenever there is no y-intercept, the slope starts at 0.

6 0
2 years ago
Phones-R-Us charges $16.95 per month and $0.05 per text message. Awesome Wireless charges $22.95 per
Dima020 [189]

Answer:

S \leq 200

Step-by-step explanation:

Given

Phone R-Us= $16.95 + $0.05 per SMS

Awesome Wireless = $22.95 + $0.02 per SMS

Required

Determine the number of SMS such that Awesome Wireless is greater or equal to Phone R-Us

Represent the SMS with S

For Phone R-Us, we have:

SMS = 16.95 + 0.05S

For Awesome Wireless, we have:

SMS = 22.95 + 0.02S

For Awesome Wireless is greater or equal to Phone R-Us, we have:

22.95 + 0.02S \geq 16.95 + 0.05S

Collect Like Terms

0.02S - 0.05S \geq 16.95 - 22.95

-0.03S \geq -6

Solve for S

\frac{-0.03S}{-0.03} \geq \frac{-6}{-0.03}

S \leq 200

<em>Hence: for Awesome Wireless to cost more or equal to Phone R-Us, the number of SMS must not exceed 200</em>

4 0
3 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
3 years ago
Read 2 more answers
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