<h3>
Answer: 41</h3>
Work Shown:
f(x) = 6x^2 - 13
f(x) = 6(x)^2 - 13
f(-3) = 6(-3)^2 - 13 ... replace every x with -3; use PEMDAS to simplify
f(-3) = 6(9) - 13
f(-3) = 54 - 13
f(-3) = 41
THE ANSWER IS D
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Answer:
- (x -3)^2 +(y -5)^2 = 9
- x^2 +y^2 -6x -10y +25 = 0
Step-by-step explanation:
The standard form equation for a circle of radius r and center (h, k) is ...
(x -h)^2 +(y -k)^2 = r^2
For radius 3 and center (3, 5), this is ...
(x -3)^2 +(y -5)^2 = 9 . . . . standard form equation
Expanding this and subtracting the constant on the right gives ...
x^2 -6x +9 +y^2 -10y +25 -9 = 0
x^2 +y^2 -6x -10y +25 = 0 . . . . general form equation
Answer:
The percentage decrease in the number candid student pictures for the yearbook from 2015 to 2016 is approximately 9.3 percent
Step-by-step explanation:
The given data can be presented as follows
Year
Number of Photos
2015
236
2016
214
The percentage decrease in the number of candid pictures is give by the following formula

Where;
Original value for the number of pictures = 236
New value for the number of pictures = 214
Substituting the values into the equation for the percentage decrease gives;

The percentage decrease is approximately 9.3 percent.