we have
<u>Statements</u>
<u>case A)</u> The graph is a straight line.
The statement is True
Because, this is a linear equation (see the attached figure)
<u>case B)</u> The line passes through the origin.
The statement is False
Because the point 
is not a solution of the equation
Verify
Substitute the value of x and y in the equation
------> is not true
the point is not a solution
therefore
The line does not pass through the origin
<u>case C)</u> The line passes through the point 
The statement is True
Because the point is a solution of the equation
Verify
Substitute the value of x and y in the equation
------> is true
the point is a solution
therefore
The line passes through the point
<u>case D) </u>The slope of the line is 
The statement is False
Because, the slope of the line is 
<u>case E)</u> The y-intercept of the line is 
The statement is False
we know that
The y-intercept is the value of y when the value of x is equal to zero
so
For 
find the value of y
the y-intercept is equal to 
Answer:
??????????
Step-by-step explanation:
Answer:
14cm
Step-by-step explanation:
To find volume, you need to multiply the height width and length together. So when you have one missing measurement, to find it, you need to do the same steps except for put a variable for the missing measurement. And continue to do the problem as you would. Here is how I solved it.
V=12x18xH
3024=216xH (216 is 12x18)
Then to find the missing side, do 3024/216 which equals 14.
Answer:
- 12 ft parallel to the river
- 6 ft perpendicular to the river
Step-by-step explanation:
The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.
72 = W(2W)
36 = W²
6 = W . . . . . . the width perpendicular to the river
12 = 2W . . . . the length parallel to the river
_____
<em>Development of this relation</em>
Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...
A = xy = x(T -x)/2
Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...
x = (0 +T)/2 = T/2
The corresponding area width (y) is ...
y = (T -T/2)/2 = T/4
Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.
