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3 years ago

PLEASE HELP EASY MATH PLEASE ASAP

Mathematics

1 answer:

Sedbober [7]3 years ago

4 0

Answer:

Step-by-step explanation:

I don't really know what your question is asking for but I can tell you there's a quadratic formula that solves for x-ints. There's a quadratic equation which is Ax + bx + c = 0.

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HELP MATH SUCKSSSSSSSSSSSS

Ivanshal [37]

Answer:

$\huge\boxed{\sf Slope = \frac{1}{11} }$

Step-by-step explanation:

Given coordinates are (6,-3) and (-5,-4).

$\sf Slope = \frac{y2-y1}{x2-x1}\\\\Slope = \frac{-4+3}{-5-6} \\\\Slope = \frac{-1}{-11} \\\\Slope = \frac{1}{11} \\\\\rule[225]{225}{2}$

Hope this helped!

<h3>~AnonymousHelper1807</h3>

4 0

3 years ago

A data set includes 103103 body temperatures of healthy adult humans having a mean of 98.998.9degrees°f and a standard deviation

dangina [55]

Answer:

$98.9-2.62\frac{0.65}{\sqrt{103}}=98.73$

$98.9+2.62\frac{0.65}{\sqrt{103}}=99.07$

So on this case the 99% confidence interval would be given by (98.73;99.07)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=98.9$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=0.65 represent the sample standard deviation

n=103 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=103-1=102$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,102)".And we see that $t_{\alpha/2}=2.62$

Now we have everything in order to replace into formula (1):

$98.9-2.62\frac{0.65}{\sqrt{103}}=98.73$

$98.9+2.62\frac{0.65}{\sqrt{103}}=99.07$

So on this case the 99% confidence interval would be given by (98.73;99.07)

6 0

3 years ago

Read 2 more answers

Divide £52 in the ratio 11:2

True [87]

First, get the sum of the ratio. (11 + 2 = 13)

Divide 52 by 13 to find one 'part' of the ratio. (52 ÷ 13 = 4)

Now that we have one 'part' of the ratio, we multiply it by 11 and 2 to get: (£4 × 11 = £44) and (£4 × 2 = £8).

The ratio will be £44:8.

We can check if this is correct by adding 44 and 8 to see if it adds up to 52. (44 + 8 = 52). It does, so it's correct.

6 0

3 years ago

Help me please m, it due soon

allsm [11]

Surface area= 2(6x15)+2(7x15)+2(6x7)
=180+210+84
=474m

Volume=15x6x7
=630m^2

5 0

3 years ago

Which of the binomials below is a factor of this trinomial x^2+14x+40

san4es73 [151]

$x^2+14x+40=\\
x^2+4x+10x+40=\\
x(x+4)+10(x+4)=0\\
(x+10)(x+4)$

So it's D.

8 0

3 years ago

Read 2 more answers