Answer:
(-1/3; 4)
Step-by-step explanation:
(-2, -1) , (-1, 6 ) and (2, 7).
x=(-2-1+2)/3= -1/3
y=(-1+6+7)/3=12/3=4
=> (-1/3; 4)
A) Y U Z { B, C, D, F, G, H, K, T, L, M, N, W}
b) n(YUZ) {5} (<em>n</em> is the number of elements in the set)
c) X AND Y {K}
d) n(X AND Y) {16}
I'm not sure of that notation for e and f. Can you tell me what the X\Y means?
Answer:
4a^4·b^5
Step-by-step explanation:
The applicable rule of exponents is ...
(x^a)(x^b) = x^(a+b)
The commutative and associative properties of multiplication apply, so we can write the expression as ...
4·(a^3·a)·(b^2·b^3) = 4·a^(3+1)·b^(2+3) = 4·a^4·b^5
Answer:
x=25/64
Step-by-step explanation:
by simple substitution
Answer:
C.
and 
Step-by-step explanation:
You have the quadratic function 
to find the solutions for this equation we are going to use Bhaskara's Formula.
For the quadratic functions 
with 
the Bhaskara's Formula is:
It usually has two solutions.
Then we have where a=2, b=-1 and c=1. Applying the formula:
Observation: 
And,
Then the correct answer is option C.
and
