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lbvjy [14]
2 years ago
14

Find the profit-maximizing price.

Mathematics
1 answer:
ziro4ka [17]2 years ago
3 0

Answer: \$11.5

Step-by-step explanation:

Given

Demand function is p=22-2q

The average cost function is c=2+q

Total revenue is the product of demand and the price per unit.

r=\left(22-2q\right)q

Profit is given by the difference of the total revenue and the cost

\Rightarrow P=r-c\\\Rightarrow P=22q-2q^2-2-q\\\Rightarrow P=-2q^2+21q-2

Find the derivative of profit to get the maximum profit

\Rightarrow P'=-4q+21\\\text{Put the derivative equal to 0 to get the maximum profit}\\\\\Rightarrow q=\dfrac{21}{4}

Put q in the equation of demand to get the price

\Rightarrow p=22-2\times \dfrac{21}{4}\\\\\Rightarrow p=22-10.5\\\Rightarrow p=\$11.5

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Answer:

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Step-by-step explanation:

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Lena [83]

Answer:

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Step-by-step explanation:

Step(i):-

Given     - 2 √3 + √75

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By using

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2 years ago
Dividing Mixed fractions
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Step-by-step explanation:

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2. Describe how to use the conjugate to divide 2 − i by 3 + 2i, and then find the quotient.
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\frac{2-i}{3+2i}

Multiply and divide by the conjugate.

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\frac{2-i}{3+2i}\frac{3-2i}{3-2i}\\ =\frac{2\times (3-2i)-i\times (3-2i)}{3^2-(2i)^2}\\ =\frac{6-4i-3i+2i^2}{9+4}\\ =\frac{4-7i}{13}\\ =\frac{4}{13}-\frac{7}{13}i

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